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steposvetlana [31]
3 years ago
13

The difference of this equation.

Mathematics
1 answer:
yaroslaw [1]3 years ago
4 0

Answer:

\frac{23}{(y-8)(y+8)}=\frac{23}{y^{2}-64}

Step-by-step explanation:

\frac{3y - 1}{(y-8)(y+8)} -\frac{3}{y+8} = \frac{3y - 1}{(y-8)(y+8)} -\frac{3(y-8)}{(y-8)(y+8)} =\\\\=\frac{3y - 1-3y+24}{(y-8)(y+8)} = \frac{23}{(y-8)(y+8)}=\frac{23}{y^{2}-64}

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