Answer:
The value of a is 10.
Step-by-step explanation:
We are given with the following pair of the linear system of equations below;
and
.
Also, the solution is given as (a, -1).
To find the value of 'a', we have to substitute the solution in the equation because it is stated that (a, -1) is the solution of the given two equations.
So, the x coordinate value of the solution is a and the y coordinate value of the solution is (-1).
First, taking the equation;
Put the value of x = a and y = -1;
(-1) = -(a) + 9
a = 9 + 1 = 10
Now, taking the second equation;

Put the value of x = a and y = -1;

0.5a = 6 - 1
0.5a = 5
a = 10
Since we get the value of a = 10 from the equations, so the value of a is 10.
Least common multiple question
Ronald: count by 6's
6, 12, 18, 24, 30, 36, 42, 48, 54 ....
Tim: count by 9's
9, 18, 27, 36, 45, 54,
every 18 days they do their laundry together
The possible values for | x-y | > 0 is any number above 0. x must be greater than y. When | x-y | = 0, That means that x and y are equal to each other. | x-y | can not be less than 0, but it can equal 0.
Hope that this helped!
He has a 26% of getting a strike, which means he has a 74% chance of not getting a strike ( 100% - 26% = 74%).
Multiply the chance of not getting a strike by the number of attempts:
0.74 x 0.74 x 0.74 x 0.74 x 0.74 = 0.22
The answer is B) 0.22
The probability of making a free throw is 77%, the probability of not making one would be 23% ( 100% - 77% = 23%).
Add the probability of making the first one ( 0.77) by the probability of making the second one multiplied by the probability of missing the second one ( 0.77x 0.23)
0.77 + (0.77 x 0.23)
0.77 + 0.18 = 0.95
The answer is D) 95%
Answer:
a) = 4.5
b) = 3.3
Step-by-step explanation:
Before solving our problems given to us let us under stand the rule of cube roots
It says
-----(A)
Also
---(B)
Now let us see each part one by one
a) we have
![\sqrt[3]{64} + \sqrt[3]{0.027} + \sqrt[3]{0.008}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D%20%2B%20%5Csqrt%5B3%5D%7B0.027%7D%20%2B%20%5Csqrt%5B3%5D%7B0.008%7D)
Now 64 = 4 x 4 x 4
0.027 = 0.3 x 0.3 x 0.3
0.008 = 0.2 x 0.2 x 0.2
substituting these values
![\sqrt[3]{4 \times 4 \times 4} + \sqrt[3]{0.3 \times 0.3 \times 0.3} + \sqrt[3]{0.2 \times 0.2 \times 0.2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B4%20%5Ctimes%204%20%5Ctimes%204%7D%20%2B%20%5Csqrt%5B3%5D%7B0.3%20%5Ctimes%200.3%20%5Ctimes%200.3%7D%20%2B%20%5Csqrt%5B3%5D%7B0.2%20%5Ctimes%200.2%20%5Ctimes%200.2%7D)
Applying Rule A in above


4.5
b) we have ![\sqrt[3]{0.3 \times 0.3 \times 0.3 \times 11 \times 11 \times 11}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B0.3%20%5Ctimes%200.3%20%5Ctimes%200.3%20%5Ctimes%2011%20%5Ctimes%2011%20%5Ctimes%2011%7D)
Applying the B rule in this

3.3