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storchak [24]
3 years ago
6

PLEASEEE HURRY I WILL GIVE BRAINLEST ITS JUST ONE QUESTION

Mathematics
1 answer:
love history [14]3 years ago
7 0
I think it’s is A make me brainliest
You might be interested in
The side lengths of a triangle are 9, 12, and 15. Is this a right triangle?
andriy [413]

Answer:

<h2>Yes, this is a right triangle.</h2>

Step-by-step explanation:

Hypotenuse always have the highest number than base and perpendicular.

Hypotenuse ( h ) = 15

Base ( b ) = 9

Perpendicular ( p ) = 12

Let's see whether the given triangle is a right triangle or not

Using Pythagoras theorem:

{h}^{2}  =  {p}^{2}  +  {b}^{2}

Plugging the values,

{15}^{2}  =  {12}^{2}  +  {9}^{2}

Evaluate the power

225  = 144 + 81

Calculate the sum

225 = 225

Hypotenuse is equal to the sum of perpendicular and base.

So , we can say that the given lengths of the triangle makes a right triangle.

Hope this helps..

Best regards!!

4 0
3 years ago
Read 2 more answers
PLS HELP RN <br> $4000 student loan. 10% compound interest annually. Total loan amount by 4 years?
ddd [48]

Answer:

$2,400

Step-by-step explanation:

We get 10% of 4,000 by dividing 4,000 by 10.

4,000 ÷ 10 = 400

To get the amount that 4,000 is subtracted by we multiply 400 by 4.

400 × 4 = 1,600

To get the answer we subtract 4,000 by 1,600.

4,000 - 1,600 = 2,400

Hope I helped!

3 0
3 years ago
What additional information could be used to prove ΔABC ≅ ΔMQR using SAS? Select two options. m∠A = 64° and AB = MQ = 31 cm CB =
enyata [817]

Answer:

m∠R = 60° and AB ≅ MQ

m∠Q = 56° and CB ≅ RQ

Step-by-step explanation:

Given data :

Prove ΔABC ≅ ΔMQR using SAS

The  missing information to prove ΔABC ≅ ΔMQR using SAS

  • m∠R = 60° and AB ≅ MQ
  • m∠Q = 56° and CB ≅ RQ
3 0
3 years ago
Read 2 more answers
What are the solutions of x^2+5x=2? Check all that apply
astraxan [27]
X^2+5x=2
you then solve by completing the square using the formula (b/2)^2 in order to create the new term. Solve for x by using this term to complete the square. 
Your answer is then
x=-5/2+-√33/2
3 0
3 years ago
Read 2 more answers
Two mechanics worked on a car. the first mechanic worked for 10 hours, and the second mechanic worked for 15 hours. together the
Yuliya22 [10]
Let x and y be the rate per hour for Mechanic 1 and 2 respectively.

Then,
x+y=205 ---------- (1)
Additionally,
10x+15y = 2500 ------ (2)

Solving equations 1 and 2;
Multiply (1) by 10 and subtract two from the result,
10x+10y = 2050
10x +15 y =2500
----------------------
        -5 y = --450 => y = 450/5 = $90
Then,
x= 205-90 = $115

Therefore,
Mechanic 1 charged $115 per hour
Mechanic 2 charged $90 per hour
3 0
3 years ago
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