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Anna71 [15]
3 years ago
5

If the star Alpha Centauri were moved to a distance 10 times farther than it is now, its parallax angle would

Physics
1 answer:
7nadin3 [17]3 years ago
4 0

Answer:

decrease by a factor 10

Explanation:

The parallax angle of a close star is given by

p=\frac{1}{d}

where

p is the parallax angle

d is the distance of the star from Earth, in parsecs

From the formula we see that the parallax angle is inversely proportional to the distance.

In this problem, the distance of the star is increased by a factor 10:

d' = 10 d

so the new parallax angle would be

p'=\frac{1}{10 d}=\frac{1}{10}\frac{1}{d}=\frac{p}{10}

So, the parallax angle would decrease by a factor 10.

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A typical reaction time to get your foot on the brake in your car is 0.2 second. If you are traveling at a speed of 60 mph (88 f
katrin [286]

Explanation:

Not enough information. It really depends on the technical details of the car ( the data provided is offering just the human factor of the reaction, not the time for getting the impulse through when using the breaks

5 0
3 years ago
Read 2 more answers
. Two parallel conducting plates are separated by 10.0 cm, and one of them is taken to be at zero volts. (a) What is the electri
exis [7]

Answer:

Explanation:

electrical field strength = potential diff / distance

= ( 450 - 0 ) / 8 x 10⁻²

= 5625 V/m

b )

potential difference = electric field x distance

= 5625 x .10

= 562.5 V

6 0
3 years ago
A motorboat accelerates uniformly from a velocity of 6.5 m/s to the west to a velocity of 1.5 m/s to the west. If its accelerati
monitta

Answer:

The displacement of the boat is 7.41 m

Explanation:

Given;

initial velocity of the motorboat, u = 6.5 m/s west

final velocity of the motorboat, v = 1.5 m/s west

acceleration of the motorboat, a = -2.7 m/s² east

The displacement of the boat is given by;

v² = u² + 2ad

where;

d is the displacement of the motorboat

1.5² = 6.5² + 2(-2.7)d

1.5² -  6.5² = -5.4d

-40 = -5.4d

d = (40) / 5.4

d = 7.41 m

Therefore, the displacement of the boat is 7.41 m

6 0
4 years ago
Find the kinetic energy of a 0.1-kilogram toy truck moving at the speed of 1.1 meters per second.
Viktor [21]

Answer:

0.061 J

Explanation:

The kinetic energy of an object is given by

K=\frac{1}{2}mv^2

where

m is the mass of the object

v is its speed

For the toy truck in the problem, we have

m = 0.1 kg is its mass

v = 1.1 m/s is its speed

Putting the numbers into the equation, we find

K=\frac{1}{2}(0.1 kg)(1.1 m/s)^2=0.061 J

6 0
4 years ago
ver shines light up to the surface of a flat glass-bottomed boat at an angle of 30 relative to the normal. If the index of refr
Free_Kalibri [48]

Answer:

\beta = 41.68°

Explanation:

according to snell's law

\frac{n_w}{n_g} = \frac{sin\alpha}{sin30 }

refractive index of water n_w is 1.33

refractive index of glass  n_g  is 1.5

sin\alpha = \frac{n_w}{n_g}* sin30

sin\alpha = 0.443

now applying snell's law between air and glass, so we have

\frac{n_g}{n_a} = \frac{sin\alpha}{sin\beta}

sin\beta = \frac{n_g}{n_a} sin\alpha

\beta = sin^{-1} [\frac{n_g}{n_a}*sin\alpha]

we know that sin\alpha = 0.443

\beta = 41.68°

7 0
3 years ago
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