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Charra [1.4K]
3 years ago
12

Can someone help ASAP pleasee

Physics
1 answer:
UkoKoshka [18]3 years ago
8 0

Answer:

C.

Explanation:

The x axis is the origin and the degrees move counter clockwise from there so a 90° flip would be answer C.

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A substance made up of only one type of element
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A 6 m long, uniform ladder leans against a frictionless wall and makes an angle of 74.3 ◦ with the floor. The ladder has a mass
olganol [36]

Answer: µ=0.205

Explanation:

The horizontal forces acting on the ladder are the friction(f) at the floor and the normal force (Fw) at the wall. For horizontal equilibrium,

f=Fw

The sum of the moments about the base of the ladder Is 0

ΣM = 0 = Fw*L*sin74.3º - (25.8kg*(L/2) + 67.08kg*0.82L)*cos74.3º*9.8m/s²

Note that it doesn't matter WHAT the length of the ladder is -- it cancels.

Solve this for Fw.

0= 0.9637FwL - (67.91L)2.652

Fw=180.1/0.9637

Fw=186.87N

f=186.81N

Since Fw=f

We know Fw, so we know f.

But f = µ*Fn

where Fn is the normal force at the floor --

Fn = (25.8 + 67.08)kg * 9.8m/s² =

910.22N

so

µ = f / Fn

186.81/910.22

µ= 0.205

4 0
3 years ago
Suppose that a block of mass 2 kg is pulled to the right with a force of 10 N, and the friction force on the block is directed t
Law Incorporation [45]

Answer:

The block has an acceleration of 3 m/s^{2}

Explanation:

By means of Newton's second law it can be determine the acceleration of the block.

\sum F_{r} = ma   (1)

Where \sum F_{r} represents the net force, m is the mass and a is the acceleration.

F_{x} + F{y} = ma  (2)

The forces present in x are F = 10 N and f = 4 N (the friction force):

F_{x} = 10 N - 4 N

Notice that f subtracts to F since it is at the opposite direction.

F_{x} = 6 N

The forces present in y balance each other:

F_{y} = 0

Therefore:

6 + 0 = ma  

6 N = (2kg)a  (3)

But 1 N = 1 Kg.m/s^{2} and writing (3) in terms of a it is get:

a = \frac{6 Kg.m/s^{2}}{2 Kg}  

a = 3 m/s^{2}

So the block has an acceleration of a = 3 m/s^{2}.

4 0
3 years ago
A chunk of paraffin (wax) has a mass of 50.4 grams and a volume of 57.9 cm3. What is the density of
ExtremeBDS [4]
Formula\ for\ density:\\\\
p=\frac{m}{V}\\p-density,\\m-mass,\\V-volume\\\\
Data:\\
m=50,4grams\\
V=57,9cm^3\\\\
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An oscillating block-spring system has a mechanical energy of 4.72 J, an amplitude of 11.2 cm, and a maximum speed of 4.24 m/s.
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Answer:

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