Question

An iron vat is 11 m long at room temperature (20°C). How much longer is it when it contains boiling water at 1 atm pressure?

Answer 1

Answer:

The change in length is 0.01056 m.

Explanation:

Given that,

Length = 11 m

Temperature = 20°C

Pressure = 1 atm

Boiling temperature = 100°C

We need to calculate the length

Using formula of change in linear expansion

$\dfrac{\Delta L}{L}=\alpha_{l}\Delta T$

$\Delta L=L\times\alpha_{l}\times(T_{f}-T_{i})$

Put the value into the formula

$\Delta L=11\times12\times10^{-6}\times(100-20)$

$\Delta L=11\times12\times10^{-6}\times80$

$\Delta L=0.01056\ m$

Hence, The change in length is 0.01056 m.