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masha68 [24]
4 years ago
12

Solve the system by substitution. x – 3y = 4 2x – 6y = 8 A. no solution B. x = 4, y = 0 C. x = 0, y = 0 D. infinite solutions

Mathematics
2 answers:
Gwar [14]4 years ago
5 0

Answer:

A

Step-by-step explanation:

1. Isolate the x-term in the first equation:

     x-3y=4 -> x=3y+4

2. Substitute <em>3y+4</em> in for x in the second equation and solve

     2(3y+4)-6y=8 : Distribute the 2

     6y+8-6y=8 : Combine like terms

     8=8

3. Isolate the y-term in the first equation:

    x-3y=4 -> -3y=-x+4

 a. Solve for y:

       (-3y=-x+4)/-3 : Divide by -3

       y=(1/3)x-(4/3)

4. Substitute (1/3)x-(4/3) in for y in the second equation and solve:

     2x-6((1/3)x-(4/3))=8 : Distribute the -6

     2x-2x+8=8 : Combine like terms

     8=8

Explanation:

When you solve a system of equations and get a true statement-

The lines are parallel.

Parallel lines will never intersect, so there is no solution.

     

ruslelena [56]4 years ago
4 0

Answer:

The correct answer is option D.

Step-by-step explanation:

if the pair of equation has one or more than one solution then it is said to be consistent.

  • Only one solution , then independent system.
  • More than one solution , then dependent system.

if the pair of equation has no solution then it is said to be inconsistent.

Given : x - 3y = 4 ...[1]

2x - 6y = 8 ...[2]

Solution :

Solving equations with the help of Substituting methods:

x - 3y = 4

x = 4 +3y

Putting value of x from [1] in [2]:

2(4+3y)-6y=8

8+6y-6y=8

6y=6y

0 = 0

Given , system of equation will have infinite solution. Hence consistent and dependent.

The given system of equations will have infinite solutions.

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algol [13]

Answer:

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Step-by-step explanation:

Given a car's cost of operation is $485 for 500 miles, you want an equation relating cost for m miles, and solutions to that equation for 1200 miles, and for a cost of $820.

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<h3>Equation</h3>

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<h3>1200 miles</h3>

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<h3>$820</h3>

The number of miles that can be driven for a cost of $820 is ...

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About 845 miles are driven for a cost of $820.

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