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4 years ago

What is the definition for molarity?

2 answers:

8 0

In chemistry, molarity is a concentration unit,defined to be the number of moles of solution divided by the number of liters of solution.

Akimi4 [234]4 years ago

7 0

Molarity is a concentration unit, the number of moles of solute divided by the numbers of liters in a solution. Pertaining to chem

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Setler79 [48]

Answer:

science is good U will be a genius

3 0

3 years ago

How many grams are in 0.90 mol Pd?*

maria [59]

Mass of Pd = 95.78 g which is close the the variant E) 95.89

Explanation:

To calculate the number of moles of palladium (Pd) we use the following formula:

number of moles = mass / atomic weight

mass = number of moles × atomic weight

mass of Pd = 0.90 × 106.42

mass of Pd = 95.78 g

Learn more about problems with number of moles:

brainly.com/question/3262

4 0

4 years ago

5. When argon was discovered, it was placed between chlorine and potassium, even though the periodic

Neporo4naja [7]

Because the modern periodic table is according to icnreasing atomic numbers.Ar has the atomic number 18 and potassium 19 so Argron is placed before K in the Modern periodic table.

4 0

3 years ago

A gaseous mixture at 265K and 1.0 atm contains 25 O2 60 N2 and 15 CO2 mole basis The velocities of the components are 0.084 cm s

Free_Kalibri [48]

Answer:

The molar average velocity is 0.0588 cm/s

The N₂ diffusion velocity relative to the mole average velocity is -0.1428 cm/s

The molar diffusional flux of N₂ is -3.9x10⁻³

Explanation:

Given data:

T = temperature = 265 K

O₂ = 25%

N₂ = 60%

CO₂ = 15%

vO₂ = -0.084 cm/s

vN₂ = 0.12 cm/s

vCO₂ = 0.052 cm/s

The molar average velocity is equal:

$v_{av} =(0.25*(-0.084))+(0.6*0.12)+(0.15*0.052)=0.0588cm/s$

The N₂ diffusion velocity relative to the molar average velocity is:

$v_{i} -v_{av} =-0.084-0.0588=-0.1428cm/s$

The molar diffusional flux of N₂ is:

$N_{N_{2} } =\frac{P}{RT} y_{A} (v_{i} -v_{av} )=-3.9x10^{-3}$

8 0

4 years ago

What is the vapor pressure of the pure solvent if the vapor pressure of a solution of 10 g of sucrose (C6H12O6) in 100 g of etha

amid [387]

Answer:

56.4 mmHg

Explanation:

Given:

Vapor pressure of the solution, P solution = 55 mmHg

The mass of sucrose (C₆H₁₂O₆) = 10 g

Also, Molar mass of sucrose (C₆H₁₂O₆) = 180 g/mol

So, moles = Given mass/ molar mass

Hence, moles of sucrose in the solution = 10 g / 180 g/mol = 0.05556 mol

Given that: Mass of ethanol = 100 g

Molar mass of ethanol = 46 g/mol

Hence, moles of ethanol = 100 g / 46 g/mol = 2.174 mol

Mole fraction of solvent, ethanol is:

X ethanol = 2.174 mol / (2.174 + 0.05556) mol = 0.975

Applying Raoult's Law

P solution = X ethanol*P° ethanol

<u> => P° ethanol = P solution / X ethanol = 55 mmHg / 0.975 = 56.4 mm Hg</u>

6 0

4 years ago

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