Question

A 996.9 g sample of ethanol undergoes a temperature change of -70.98 °C while releasing 62.9

Answer 1

Answer:

$c=3.71\ J/g^{\circ} C$

Explanation:

Given that,

Mass of sample, m = 996.9 g

The change in temperature of the sample, $\Delta T=-70.98^{\circ}C$

Heat produced, Q = 62.9  calories = 263173.6 J

The heat released by a sample due to change in temperature is given by :

$Q=mc\Delta T$

Where

c is the specific heat capacity

So,

$c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{263173.6}{996.9\times 70.98}\\\\c=3.71\ J/g^{\circ} C$

So, the specific heat of ethanol is equal to $3.71\ J/g^{\circ} C$.