Answer:
12
Explanation:
there are 12 because of the desnity
Answer:
The number of moles of HCl in the 250 mL volumetric flask is 0.003 moles
Explanation:
Firstly, we solve for the concentration of acid using the formula
CaVa/CbVb = nₐ/nb
where Ca is the concentration of acid
Cb is the concentration of base
Va is the volume of acid
Vb is the volume of base
nₐ is the number of moles of acid (from the equation)
nb is the number of moles of base (from the equation)
Ca × 250/0.09876 × 29.59 = 1/1
Ca = 0.09876 × 29.59/250
Ca = 0.012 M
To determine the number of moles of HCl acid present in the 250 ml volumetric flask, the formula for molarity is used
Molarity = number of moles ÷ volume (in liter or dm³)
Volume needs to be converted to liter; 250 ml ⇒ 0.25 L
Molarity of the acid is 0.012 M
From the formula above, number of moles = molarity × volume (in liter)
number of moles = 0.012 × 0.25
number of moles of acid = 0.003 moles
Answer:
it's 4 or fish and I think
Answer:
- About 18 g of NH₄Cl will precipitate.
Explanation:
The <em>table G</em> is the graph of the solubility curves for several solutes which is attached.
The second picture identifies the solubilities for the NH₄Cl at 50ºC and 10ºC.
The solubility of NH₄Cl at 50ºC is about 52 g/ 100 g of water.
The solubility of NH₄Cl at 10ºC is about 34 g / 100 g of water.
Then, at 50ºC 100 g of water saturated with NH₄Cl contains about 52 g of NH₄Cl and 100 g of water saturated with NH₄Cl contains 34 g of NH₄Cl.
The difference, 52g - 34 g of NH₄Cl shall precipitate:
52 g - 34 g = 18g ← answer