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3 years ago

6

I also need help with this question: One day at 3:00 a.m., the temperature was -13F in Kodiak, Alaska. At 10:00 a.m., the temper

ature was 22F. What was the average change in temperature per hour?

2 answers:

insens350 [35]3 years ago

6 0

Over 7 hours the temperature changed 35 degrees
35/7 gives you 5 degrees per hour

nadezda [96]3 years ago

6 0

5 degrees per hour.....

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0.45 repeating as a fraction

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0.9090909.../2
This is the equivalent and it has no equal fraction counterpart

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What the algebraic expression for the difference of 8 and a number?

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$8-n$
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adoni [48]

9514 1404 393

Answer:

(d) 2 11/12

Step-by-step explanation:

$\dfrac{2}{3}-\dfrac{5}{4}+\dfrac{7}{2}=\dfrac{2}{3}+\left(\dfrac{14}{4}-\dfrac{5}{4}\right)=\dfrac{8}{12}+\dfrac{27}{12}=\dfrac{35}{12}=\boxed{2\dfrac{11}{12}}$

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2 years ago

Subtract.(8j³ + 9j² + 6j + 8) - (j² + 8)

german

As we did in the previous problem, we need to remove the parenthesis using distributive property so as to be able to combine like terms.

The first paranthesis is positive, so nothing changes as we remove it:

8 j^3 + 9 j^2 + 6 j + 8 - (j^2 + 8)

before removing the second parenthesis, we realize it is preceded by the negative sign of the indicated subtraction. Then as we remove the parenthesis, we flip the signs of all terms inside it:

8 j^3 + 9 j^2 + 6 j + 8 - j^2 - 8

now we combine like terms + 8 and - 8, rendering a zero "0". and we also combine the terms that contain j^2 : 9 j^2 - j^2 = 8 j^2.

Therefore, our final expression becomes:

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1 year ago

Solve the following system of equations.<br> 2x+y=3<br> I= 2y - 1<br> x=<br> y=

marin [14]

<em>Note: I am assuming your second equation is:</em>

<em>x = 2y - 1</em>

<em></em>

Answer:

The solution to the system of equations is:

x = 1

y = 1

Step-by-step explanation:

Given the system of equations

2x+y=3

x = 2y - 1

solving the system of equations using the elimination method

$\begin{bmatrix}2x+y=3\\ x=2y-1\end{bmatrix}$

Arrange equation variables for elimination

$\begin{bmatrix}2x+y=3\\ x-2y=-1\end{bmatrix}$

Multiply x-2y=-1 by2: 2x-4y=-2

$\begin{bmatrix}2x+y=3\\ 2x-4y=-2\end{bmatrix}$

subtracting the equations

$2x-4y=-2$

$-$

$\underline{2x+y=3}$

$-5y=-5$

now solve -5y = -5 for y

$-5y=-5$

Divide both sides by -5

$\frac{-5y}{-5}=\frac{-5}{-5}$

Simplify

$y=1$

For 2x+y=3 plug in y=1

$2x+1=3$

subtract 1 from both sides

$2x+1-1=3-1$

Simplify

$2x=2$

Divide both sides by 2

$\frac{2x}{2}=\frac{2}{2}$

Simplify

$x=1$

Therefore, the solution to the system of equations is:

x = 1

y = 1

8 0

3 years ago