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Nata [24]
3 years ago
7

What is the length of PR?

Mathematics
1 answer:
kicyunya [14]3 years ago
7 0

Answer:

8\sqrt{3}

Step-by-step explanation:

2/3 pi radians =   2/3 * 180 =  2  * 60 =  120 degrees

split triangle in half:

30, 60, 90  triangle

1/2 PR= 4 root   3

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Write the slope-intercept form of the line between the two points.
DENIUS [597]
Answer: Y= -5x+2
First we need to find slope
M= y2-y1/x2-x1
M= -3-2/1-0
M= -5/1
M= -5
Now using slope intercept form we can solve this equation
Y-y1=m(x-x1)
Y-2=-5(x-0)
Y-2=-5x+0
Y= -5x+2
hope this helps!!
Please tell me if I am incorrect, I enjoy learning from my mistakes:)
5 0
2 years ago
Which set of ordered pairs represents a function?
m_a_m_a [10]

Answer:

{(0, 0), (1, 2), (2, 4), (3, 4)

Step-by-step explanation:

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7 0
4 years ago
Help me with number 7 for 10 points!!!
Ket [755]
Remember this rhyme:

Hey Diddle Diddle, the medians the middle:

(Answer for your question: Median is 80%)

You add and divide for the Mean: 

( Answer for your question: Mean is 93)

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( Answer for your question: Mode is 87%)

And the range is the difference between.:

( Answer for your question: Range is 54.)

I hope this helps! :)
3 0
3 years ago
Read 2 more answers
Can someone please help me??
butalik [34]

I do believe the answer is D

6 0
3 years ago
Find an equation of the sphere with center (2, −10, 3) and radius 5. $$25=(x−2)2+(y−(−10))2+(z−3)2 use an equation to describe i
lana66690 [7]

In the x,y plane, we have z=0 everywhere. So in the equation of the sphere, we have

25=(x-2)^2+(y+10)^2+(-3)^2\implies(x-2)^2+(y+10)^2=16=4^2

which is a circle centered at (2, -10, 0) of radius 4.

In the x,z plane, we have y=0, which gives

25=(x-2)^2+10^2+(z-3)^2\implies(x-2)^2+(z-3)^2=-75

But any squared real quantity is positive, so there is no intersection between the sphere and this plane.

In the y,z plane, x=0, so

25=(-2)^2+(y+10)^2+(z-3)^2\implies(y+10)^2+(z-3)^2=21=(\sqrt{21})^2

which is a circle centered at (0, -10, 3) of radius \sqrt{21}.

3 0
3 years ago
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