The answer is square
Hope it helps
Answer:
y = (-1/3)(x + 10)
Step-by-step explanation:
The slope of the new (perpendicular) line is the negative reciprocal of the slope of the given line, which appears to be 3. Thus, the perpendicular line has the slope -1/3.
Using the slope-intercept form y = mx + b, and substituting the givens, we obtain:
y = mx + b => -6 = (-1/3)(8) + b, or
-6 = -8/3 + b. We must solve for the y-intercept, b:
Multiplying all three terms by 3 removes the fraction:
-18 = -8 + 3b. Thus, -10 = 3b, and so b must be -10/3.
The desired equation is
y = (-1/3)x - 10/3, or
y = (-1/3)(x + 10)
If you look on jiskha you will find the answer you will be looking for just type it in B
There may be more than one way in which to answer this question. I will assume that the "equation" is a linear one: f(x) = mx + b.
Then (16/3) = m(1) + b
This is one equation in two unknowns, so it does not have a unique solution. Was there more to this problem than you have shared?
If we assume that the y-intercept (b) is zero, then y = mx, and
16/3 = 1m, so that m = 16/3, and so y = (16/3)x.
Step-by-step explanation:
from the point -10 to -4 thre is a difference of 6 uints . Base 6
from the x-axis to furthest point,
there is a difference of 6 units. Height 6