Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8
Answer: I believe that you have to do e^3 to find the volume of a cube.
If you had the side, you would do a^3 (a stands for the side length)
Answer: b=-12
Step-by-step explanation:
120/-10 = -12
-10b/-10 = b
b=-12
Answer:
15 is the answer , the total people who has dogs , cats , parakeets and none is equals to <u>185</u> then from 200 you minus 185 which is 15 so 15 people had parakeets only
The answer will be the last one as it equals 4x + 3. this means that the equation will be parallel and does not have a solution.
