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3 years ago

Find the equation of a line having slope -8 and y intercept -3

Mathematics

1 answer:

Andre45 [30]3 years ago

5 0

Answer:

y = -8x -3

Step-by-step explanation:

To find the y intercept of a basic y = mx + b equation you simply find the constant (In Algebra, a constant is a number on its own, or sometimes a letter such as a, b or c to stand for a fixed number). To find the slope of a basic y = mx + b equation find the value of m. The value of m will be the slope.

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I need help factoring this expression

omeli [17]

X^2(x+2)-4(x+2)

(x^2-4) (x+2) = 0

do you have to keep going/?

or thats all they want?

3 0

3 years ago

Write the equation of the line in fully simplified slope-intercept form.

Aneli [31]

Answer:

$y = -\frac{1}{5}x -1$

Step-by-step explanation:

Given

The attached graph

Required

Determine the line equation

First, list out two points from the graph

$(x_1,y_1) = (-5,0)$

$(x_2,y_2) = (0,-1)$

Next, calculate the slope (m)

$m = \frac{y_2 - y_1}{x_2 - x_1}$

$m = \frac{-1-0}{0 -(-5)}$

$m = \frac{-1}{0 +5}$

$m = -\frac{1}{5}$

The equation in slope intercept form is:

$y = m(x - x_1) + y_1$

This gives:

$y = -\frac{1}{5}(x - (-5)) + 0$

$y = -\frac{1}{5}(x +5)$

Open bracket

$y = -\frac{1}{5}x -1$

4 0

3 years ago

The price of a sofa was reduced from $250 to $180. By what percentage was the price

Inessa [10]

Answer:

the price was reduced by 28%

7 0

3 years ago

Read 2 more answers

On a team, 8 girls and 7 boys scored a total of 128 points. The difference between the number of points scored by the eight girl

andriy [413]

Answer:

Step-by-step explanation:

128-16=112

112÷15(boys+girls)=7.4666666

7.4666666 rounds to 8

7 0

3 years ago

Read 2 more answers

Find the discriminant and determine the nature of the roots to the quadratic equation

Katen [24]

№17
$x^{2} +6x-7=0 \\ D=6 ^{2} -4*(-7)=36+28=64=8 ^{2} \\ \\ x_{1} = \frac{-6+8}{2} =1 \\ \\ x_{2} = \frac{-6-8}{2} =-7$
Answer: x₁ = 1
   x₂ = - 7

№18
$2 x^{2} -3x+4=3 \\ 2 x^{2} -3x+4-3=0 \\ 2 x^{2} -3x+1=0 \\ \\ D= -3 ^{2} -4*2=9-8=1 \\ \\ x_{1} = \frac{3+1}{2*2} = \frac{4}{4} =1 \\ \\ x_{2} = \frac{3-1}{2*2} = \frac{2}{4} =0.5$
Answer: x₁ = 1
     x₂ = 0,5.

№19
$2 x^{2} -4x-5=0 \\ D=-4 ^{2} -4*2*(-5)=16+40=56 \\ \\ x_{1}= \frac{4+ \sqrt{56} }{2*2} = \frac{4}{4} + \sqrt{ \frac{56}{16} } =1+ \sqrt{3.5} \\ \\ x_{2} = \frac{4- \sqrt{56} }{2*2} = \frac{4}{4} - \sqrt{ \frac{56}{16} } =1- \sqrt{3.5} 
$
Answer: x₁ = 1 + √3.5
     x₂ = 1 - √3.5

3 0

3 years ago