Answer:
X = 'is the athlete injured' (X in {0,1})
Y = 'the athlete wins' (Y in {0,1})
P(Y=1|X=0) = 0.75
P(Y=1|X=1) = 0.15
P(Y=1) = 0.51
We are looking for P(X=1) - P(Y=1) = P(Y=1|X=0)*(1-P(X=1)) + P(Y=1|X=1)*P(X=1)
The above equation should provide you with the answer 0.4!
Step-by-step explanation:
Answer:
Step-by-step explanation:
-7(x-3)
y-1+1=-7x+21
y=-7x+22
False
Because the left side comes out to a sum of 40 while 15-7 equals 8 and 24 times 3 equals 72 72 plus 8 equals 80 divided by 2 equals 40 and 8 times 9 equals 72 plus 6 equals 78 plus 6 equals 84
Answer:

The doubling time is of 27.65 minutes.
Step-by-step explanation:
Exponential equation of growth:
The exponential equation for population growth is given by:

In which P(0) is the initial value and k is the growth rate.
A freshly inoculated bacterial culture of Streptococcus contains 100 cells.
This means that
. So

When the culture is checked 60 minutes later, it is determined that there are 450 cells present.
This means that
, and we use this to find k. So






So

Doubling time:
This is t for which P(t) = 2P(0) = 200. So






The doubling time is of 27.65 minutes.