both angles would equal the same so you have:
6x-57 = 2x+15
add 57 to each side:
6x = 2x+72
subtract 2x from each side:
4x = 72
divide:
x = 72/4 = 18
now replace x with 18:
6(18) - 57 = 51
2(18) +15 = 51
51 +51 = 102
Angle QNR = 102 degrees
Answer:
Hi How are you doing today???
<span>Length of outer track = sum of length of 10 pieces = circumference of the outer circle
if R is the Radius of outer circle then...
Circumference of the outer track = 2pi*R
Similarly the circumference of the inner track (with radius r) = 2pi*r
length of each outer piece is 3.4 inch more than length of inner piece
So total outer length is 10*3.4 =34 inches more than the inner length.
=> Outer Circumference - Inner Circumference = 34 inches
=> 2pi*R - 2pi*r = 34
=> 2pi(R -r) = 34
=> R-r = 34/2pi = 5.41 inches
=> R-r = Width of the track = 5.41 inches</span>
All to one side:
4x^2-32x+64 = 0,
divide by 4:
x^2 -8x + 16 = 0
apply formula or see that it is (x-4)^2!, so only x =4 is a root and it is double.
