What is the equation for a line with a slope of 5 and a y-intercept of 11?

Which real-world story is represented by the addition problem (–2 1/2) + (–3 1/4) = –5 3/4?

allochka39001 [22]

Answer:

A

Step-by-step explanation:

A is the correct answer because the equation matches option A.

(-2 1/2) + (-3 1/4)

The minus sign in -2 1/2 shows that the submarine descended and then descended again with the addition sign. Though the addition sign can mean that it ascended its incorrect.

With the equation in hand, we can prove that option A is correct.

If the submarine descended 2 1/2 miles then here must be a minus sign next to the 2 1/2. But if it ascended then there would've been an addition sign to show that it ascended. The other value - 3 1/4 also shows that it ascended with the help of the addition sign.

Ascends - values increase from smallest to highest.

Descends - values decrease from highest to smallest.

4 0

3 years ago

The store is 15 min. away from my house, it takes 30 min. to get to and from the store. How come my dad isn't back with milk yet

coldgirl [10]

Answer:

What dad?

Step-by-step explanation:

he ran away. or hes with somebody

8 0

3 years ago

Read 2 more answers

Hi, I need an answer to this question pls. Louisa used Uber which charges $2 for the first mile and $1.10 for each additional mi

Vanyuwa [196]

Answer:

20 miles

Step-by-step explanation:

Let x = amount charge each mile

y = total price paid

Since the Uber charged $1.10 for each mile, we multiply x by 1.1 like this 1.1x

Also, $2 were already charged so we add 2 to the total price

y = 1.1x + 2

Since the Lyft charged $0.95 for each mile, we multiply x by 0.95 like this 0.95x

Also, $5 were arleady charged so we add 5 to the total price

y = 0.95x + 5

We have to find a price where both rides match

1.1x + 2 = 0.95x + 5

Let's move the like terms to one side by subtracting 0.95x from both sides

1.1x + 2 = 0.95x + 5

-0.95x -0.95x

0.15x + 2 = 5

Now, subtract 2 from both sides

0.15x + 2 = 5

- 2 - 2

0.15x = 3

Finally, divide both sides by the coefficient, 0.15, to isolate the variable, x

0.15x/0.15 = 3/0.15

x = 20

This means they traveled 20 miles if they were to pay the same price

7 0

3 years ago

Eli invested $ 330 $330 in an account in the year 1999, and the value has been growing exponentially at a constant rate. The val

Cloud [144]

Answer:

The value of the account in the year 2009 will be $682.

Step-by-step explanation:

The acount's balance, in t years after 1999, can be modeled by the following equation.

$A(t) = Pe^{rt}$

In which A(t) is the amount after t years, P is the initial money deposited, and r is the rate of interest.

$330 in an account in the year 1999

This means that $P = 330$

$590 in the year 2007

2007 is 8 years after 1999, so P(8) = 590.

We use this to find r.

$A(t) = Pe^{rt}$

$590 = 330e^{8r}$

$e^{8r} = \frac{590}{330}$

$e^{8r} = 1.79$

Applying ln to both sides:

$\ln{e^{8r}} = \ln{1.79}$

$8r = \ln{1.79}$

$r = \frac{\ln{1.79}}{8}$

$r = 0.0726$

Determine the value of the account, to the nearest dollar, in the year 2009.

2009 is 10 years after 1999, so this is A(10).

$A(t) = 330e^{0.0726t}$

$A(10) = 330e^{0.0726*10} = 682$

The value of the account in the year 2009 will be $682.

4 0

3 years ago

Paul started work at company b ten years ago at the salary of 30,000 starting year and 2400 for yearly salary increase at the sa

Cloud [144]

Sharla, earned 2,000 more than Paul

6 0

3 years ago