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aivan3 [116]
3 years ago
8

If 2x+3 is a factor of 6x^2+3x+n , what is the value of n

Mathematics
1 answer:
Vanyuwa [196]3 years ago
6 0
We will use factor to calculate zero of the eq. Then putting the value of zero in place of x we can get the value of n.plz see pic for complete solution

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Tracy recieves payments of $X at the end of each year for n years. The present value of her annuity is 493. Gary receives paymen
vladimir1956 [14]

Answer:

v = 1/(1+i)

PV(T) = x(v + v^2 + ... + v^n) = x(1 - v^n)/i = 493

PV(G) = 3x[v + v^2 + ... + v^(2n)] = 3x[1 - v^(2n)]/i = 2748

PV(G)/PV(T) = 2748/493

{3x[1 - v^(2n)]/i}/{x(1 - v^n)/i} = 2748/493

3[1-v^(2n)]/(1-v^n) = 2748/493

Since v^(2n) = (v^n)^2 then 1 - v^(2n) = (1 - v^n)(1 + v^n)

3(1 + v^n) = 2748/493

1 + v^n = 2748/1479

v^n = 1269/1479 ~ 0.858

Step-by-step explanation:

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Write the equation of each ellipse in standard form with the given characteristics.
Eddi Din [679]

Answer:

Step-by-step explanation:

The foci are horizontally aligned.

horizontal ellipse:

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b = 5

foci (h±3√19, 6)

c = 3√19

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90x0.15=13.5
 
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