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Vesna [10]
3 years ago
10

Alvin is 15 years younger than Elga. The sum of their ages is 25. What is Elga’s age

Mathematics
1 answer:
Fynjy0 [20]3 years ago
4 0
Elga is 20 years old and Alvin would be 5. Hope this helped.
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What is the value of k in the function f(x)=112-kx if f(-3)=121
Allisa [31]
F(-3)=121=112-k(-3)

121=112+3k
minus 112 both sides
9=3k
divide by 3
k=3
8 0
2 years ago
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There are 60 animal exhibits at the local zoo. What percent of the zoo's exhibits does each animal class represent?​
snow_lady [41]

Answer:

30+15+12+3=  60

for mammal 30/60=0.50%

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fish  12/60= 0.20%

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i hope that helps

8 0
3 years ago
What does 8.3 × 10^ -5 in standard notation ​
xz_007 [3.2K]

Answer:

0.000083

Step-by-step explanation:

When you multiply by 10^-5, you're really multiplying by 0.00001. This multiplied by 8.3 is 0.000083. It also means that you just move the decimal place in 8.3 to the left five times, where you'll get the same answer.

6 0
2 years ago
1. Use the cosine and sine functions to express the exact coordinates of P in terms of angle θ.
Luden [163]

Answer:

For a point defined bt a radius R, and an angle θ measured from the positive x-axis (like the one in the image)

The transformation to rectangular coordinates is written as:

x = R*cos(θ)

y = R*sin(θ)

Here we are in the unit circle, so we have a radius equal to 1, so R = 1.

Then the exact coordinates of the point are:

(cos(θ), sin(θ))

2) We want to mark a point Q in the unit circle sch that the tangent has a value of 0.

Remember that:

tan(x) = sin(x)/cos(x)

So if sin(x) = 0, then:

tan(x) = sin(x)/cos(x) = 0/cos(x) = 0

So tan(x) is 0 in the points such that the sine function is zero.

These values are:

sin(0°) = 0

sin(180°) = 0

Then the two possible points where the tangent is zero are the ones drawn in the image below.

7 0
3 years ago
What is (-0.8)(-0.8)(-0.8)
puteri [66]
The answer would be -0.512
You would get this answer because -0.8 times -0.8 equals 0.64. Positive 0.64 times negative 0.8 would result In -0.512
8 0
2 years ago
Read 2 more answers
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