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kifflom [539]
3 years ago
7

Please help me with this question!! Thank you so much, it should be quick. I need to know what goes in the blank space above.

Mathematics
2 answers:
katovenus [111]3 years ago
4 0
Ratio works for the blank space. Since scale factor and ratio are synonyms. They both refer to the rate of change of something. 
Ipatiy [6.2K]3 years ago
3 0
If two objects have the same shape, they are called "similar." When two figures are similar, the ratios of the lengths of their corresponding sides are equal so the word would be ratio
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Express 5.26 x 10^6 in standard form.
Alex

Answer:

5260000x

Step-by-step explanation:

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Which transformations will produce similar, but not congruent, figures?
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The correct answer is <span>A. Triangle TUV is dilated by a scale factor of 9 and then translated 2 units right and 1 unit down to form triangle TꞌꞌUꞌꞌVꞌꞌ.
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Congruent figures are of the same shape and the same size. <span>Triangle TUV is dilated by a scale factor of 9 and then translated 2 units right and 1 unit down to form triangle TꞌꞌUꞌꞌVꞌꞌ will produce similar but not congruent figures because they have different sizes.</span>
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3 years ago
9-4(2p-1) = 45 solve for p
katrin [286]

Answer: p = -4

Step-by-step explanation:

9-4(2p-1) = 45

9-8p+4 = 45

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3 years ago
When citric acid reacts with baking soda, a salt, water and a gas are produced. What is the name of the gas?
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1. y = x2 + 8x + 15<br> Find the zeros of the function by rewriting the function in intercept form
lubasha [3.4K]

The zeros of given function y=x^{2}+8 x+15 is – 5 and – 3

<u>Solution:</u>

\text { Given, equation is } y=x^{2}+8 x+15

We have to find the zeros of the function by rewriting the function in intercept form.

By using intercept form, we can put value of y as  to obtain zeros of function

We know that, intercept form of above equation is x^{2}+8 x+15=0

\text { Splitting } 8 x \text { as }(5+3) x \text { and } 15 \text { as } 5 \times 3

\begin{array}{l}{\rightarrow x^{2}+(5+3) x+5 \times 3=0} \\\\ {\rightarrow x^{2}+5 x+3 x+5 \times 3=0}\end{array}

Taking “x” as common from first two terms and “3” as common from last two terms

x (x + 5) + 3(x + 5) = 0

(x + 5)(x + 3) = 0

Equating to 0 we get,

x + 5 = 0 or x + 3 = 0

x = - 5 or – 3

Hence, the zeroes of the given function are – 5 and – 3

5 0
3 years ago
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