Plz help me!!

STEP-BY-STEP SOLUTION:

( x + 4 )^2 + y^2 = 22

x^2 + 2 × x × 4 + 4^2 + y^2 = 22

x^2 + 8x + 16 + y^2 = 22

y^2 = 22 - x^2 - 8x - 16

y^2 = - x^2 - 8x + 6

FINAL ANSWER:

Therefore, the answer is:

D. y^2 = - x^2 - 8x + 6

Please mark as brainliest if you found this helpful! :)
Thank you <3

6 0

3 years ago

BRAINLIEST ASAP!!!!

ivanzaharov [21]

The graph of a quadratic equation is a U-shaped curved called parabola. It is because the parabola makes very easy to find the axis of symmetry to plot selected points and finding the roots and vertex.

Good luck :)

4 0

3 years ago

There are 14 juniors and 16 seniors in a chess club. a) From the 30 members, how many ways are there to arrange 5 members of the

Dmitrij [34]

Answer:

a) 17,100,720

b) 4,717,440

c) 10,920

d) 2821

Step-by-step explanation:

14 juniors and 16 seniors = 30 people

a) From the 30 members, how many ways are there to arrange 5 members of the club in a line?

As it is a ordered arrangement

30.29.28.27.26 = 17,100,720

b) How many ways are there to arrange 5 members of the club in a line if there must be a senior at the beginning of the line and at the end of the line?

16.28.27.26.15 = 4,717,440

c) If the club sends 2 juniors and 2 seniors to the tournament, how many possible groupings are there?

Not ordered arrangement. And means that we need to multiply the results.

C₁₄,₂ * C₁₆,₂

C₁₄,₂ = 14.13.12! = 14.13 = 91

12! 2! 2

C₁₆,₂ = 16.15.14! = 16.15 = 120

14! 2! 2

C₁₄,₂ * C₁₆,₂ = 91.120 = 10,920

d) If the club sends either 4 juniors or 4 seniors, how many possible groupings are there?

Or means that we need to sum the results.

C₁₄,₄ + C₁₆,₄

C₁₄,₄ = 14.13.12.11.10! = 14.13.12.11 = 1001

10! 4! 4.3.2.1

C₁₆,₄ = 16.15.14.13.12! = 16.15.14.13 = 1820

12! 4! 4.3.2.1

C₁₄,₄ + C₁₆,₄ = 1001 + 1820 = 2821

7 0

3 years ago