First year:
.3 x 2593 = 777.9
$2593 - $777.90 = $1815.10
Second year:
.3 x 1815.10 = 544.53
$1815.10 - $544.53 = $1270.57
Third year:
.3 x 1270.57 = <span>381.171
$1270.57 - $381.171 = $</span>889.39900
$889.39900 rounded to the nearest hundredth is $889.40
C = 220T + 1890.
Solve the equation for T.
220T = C - 1890
T = C/220 - 8.6
The steel produced is expected to be sold at a price of $310 per ton.
310 $/ton is a rate or slope. Write a linear equation where x is tons of steel produced and y is selling price of the steel.
y = 310x
Write and solve an equation to find the amount of steel produced if the selling price is equal to the cost of production.
* Here, note that the cost of production and tons of steel in the first equation is in the millions. The equation we just wrote for the selling price was in x tons of steel. This only matters in regards to the units you specify because; million/million = 1
The unit multiplier of all variables must be specified as same. Either everything is in millions or not.
Here, I'll leave everything in millions, change x (tons of steel) to T (mill tons steel) and "y" to "S" in million dollars selling price.
S = 310T
Set equal to Cost equation.
220T + 1980 = 310T
Solve for T, million tons of steel produced.
1980 = 310T - 220T
1980 = 90T
T = 1980/90
T = 22 million tons steel produced
9514 1404 393
Answer:
5 1/16 ft
Step-by-step explanation:
h(t) = -16t(t -18/16) . . . . put in intercept form
The function describes a parabola that opens downward. It has zeros at t=0 and t=9/8. The maximum height will be found at the vertex of the parabola, halfway between these zeros.
f(9/16) = (-16)(9/16)² +18(9/16) = 81/16 = 5 1/16 . . . . feet
The approximate maximum height of the leopard is 5 1/16 feet.
You would do 5 times 4 which is 20. then count how many zero's there are and put them after the 20.
