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3(x+2)-9=15-4(5x-2)
First use the distributive property of both sides:-
3(x+2)-9=15-4(5x-2)
3x+6-9=15-20x+8
Now add 20x on both sides:-
23x+6-9=15+8
On simplification,
23x-3=23
Add 3 to both sides:-
23x=26
Divide by 23 on both sides:-
x=26/23
<h3>Good luck.</h3>
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9514 1404 393
Answer:
(a) $133.88
Step-by-step explanation:
The addition of tax multiplies the purchase price by 1+6.45% = 1.0645. The payment of the down payment means the loan amount will be only 1-10% = 0.90 times the amount with tax. So, the loan amount is ...
$22,359(1.0645)(0.90) = $21,420.08
The loan is a secured loan (secured by the vehicle). So, the interest charged is that for a poor credit rating: 7.5%.
One month's interest is ...
I = Prt . . . . . interest on principal P at rate r for t years (1 mo = 1/12 yr)
I = $21,420.08(0.075)(1/12) = $133.88
Answer:
Step-by-step explanation:
.....<em>final answer.</em>
GCF is the highest value that can divide an expression. The equivalent expression to 10x^2y + 25x^2 is 5x^2 (2y + 5)
<h3>Factoring polynomial expressions</h3>
GCF is the highest value that can divide an expression. Given the expression below
10x^2y + 25x^2
Find the factor of each
10x^2y = 5 * 2 * x^2 * y
25x^2 = 5 * 5 * x^2
Since 5x^2 is common to both factors, hence
10x^2y + 25x^2 = 5x^2 (2y + 5)
The equivalent expression to 10x^2y + 25x^2 is 5x^2 (2y + 5)
Learn more on factoring here: brainly.com/question/24734894
Answer:
Step-by-step explanation:
This car follows a line, hence its motion can be modeled by the Line equation.
In fact, we already have two points of the line, if we call the time in hours and the traveled distance in miles:
Point 1:
Since we are told the car's initial position is 300 miles in the time 0 h
Point 2:
Since we are told the car's final position is 180 miles after 3h
<u />
<u>Let's find the Slope :
</u>
This is the slope of the line
Now, the equation of the line is:
We already know the slope, now we have to find the intersection point with the y-axis () with any of the given points. Let's choose Point 1:
Isolating :
Then, the equation of the line is: