Given a term in an arithmetic sequence and the common difference, find the first five terms
1 answer:
Answer:
Step-by-step explanation:
To find the first five terms
we come with a1
a(n) = a1 +(n-1)d
a(17) = a1 +(17-1)6=71
So a1=71-96= <u>-25 </u>
first five terms:
a1= -25
a(2) = -25 +(2-1)6=<u>-19</u>
a(3) = -25 +(3-1)6=<u>-13</u>
a(4) = -25 +(4-1)6=<u>-7</u>
a(5) = -25 +(5-1)6=<u>-1</u>
<u>hope it helps</u>
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Answer:
the first five terms are
a1 = 6
a2 = 24
a3 = 60
a4 = 120
a5 = 210
Step-by-step explanation:
the experission used to find the five terms is
an = n3+ 3n2+ 2n
If it is not an integer, it would have to be a decimal.
Answer:
120 is the correct answer
thanks. please mark brainlist
Multiply back by 1/2, to get 3/22.