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oee [108]
3 years ago
14

What is the summation notation for the geometric sequence 1/2+2+8+32+128

Mathematics
2 answers:
love history [14]3 years ago
6 0
170.5 is the answer from the TI-84

expeople1 [14]3 years ago
4 0

Answer:

The sum of the given geometric series is:

                             170.5

Step-by-step explanation:

We know that for any geometric series have 'n' terms with first terms as: ''a'' and common ratio of the terms in the series as: 'r'

We get the sum of the series by the formula :

S_n=a\times (\dfrac{r^n-1}{r-1})

From the question we have:

a=1/2 , r=4 ( Since each term is the series is 4 times it's preceding term) and n=5  (as there are five terms in the series )

Hence, the sum of the series is:

S_5=\dfrac{1}{2}\times (\dfrac{4^5-1}{4-1})\\\\\\S_5=\dfrac{1}{2}\times (\dfrac{1023}{3})\\\\\\S_5=170.5

Hence, the sum of the series is: 170.5

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<h2>6</h2>

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2(16-13)\\\\\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}\\\\\mathrm{Calculate\:within\:parentheses}\:\left(16-13\right)\::\quad 3\\\\=2\times\:3\\\\= 6

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3 years ago
URGENT<br> I put an answer already but I need a confirmation!
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Suppose that a loan of $2500 is given at an interest rate of 19% compounded each year.
IrinaK [193]

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Step-by-step explanation:

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How many meters are in 0.125 kilometers?
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4 years ago
Read 2 more answers
(6-3(cube root of 6)/(cube root of 9)
MatroZZZ [7]

For this case we must simplify the following expression:

\frac {6-3 \sqrt [3] {6}} {\sqrt [3] {9}}

Multiplying the numerator and denominator by(\sqrt [3] {9}) ^ 2

\frac {6-3 \sqrt [3] {6}} {\sqrt [3] {9}} * \frac {(\sqrt [3] {9}) ^ 2} {(\sqrt [3] { 9}) ^ 2} =

We rewrite:

\frac {\frac {6-3 \sqrt [3] {6}} * (\sqrt [3] {9}) ^ 2} {\sqrt [3] {9} * (\sqrt [3] {9 }) ^ 2} =

By properties of powers we have that:

a ^ m * a ^ n = a ^ {m + n}\\\frac {(6-3 \sqrt [3] {6}) * (\sqrt [3] {9}) ^ 2} {(\sqrt [3] {9}) ^ 3} =\\\frac {(6-3 \sqrt [3] {6}) * (\sqrt [3] {9}) ^ 2} {9} =

We rewrite, moving the exponent within the radical:

\frac {(6-3 \sqrt [3] {6}) * \sqrt [3] {9 ^ 2}} {9} =\\\frac {(6-3 \sqrt [3] {6}) * \sqrt [3] {81}} {9} =

We can rewrite3 * 3 ^ 3 = 81

\frac {(6-3 \sqrt [3] {6}) * \sqrt [3] {3 * 3 ^ 3}} {9} =

We simplify:

\frac {(6-3 \sqrt [3] {6}) * 3 \sqrt [3] {3}} {9} =

We apply distributive property:

\frac {18 \sqrt [3] {3} -9 \sqrt [3] {18}} {9} =

Simplifying we finally have:

2 \sqrt [3] {3} - \sqrt [3] {18}

Answer:

2 \sqrt [3] {3} - \sqrt [3] {18}

5 0
3 years ago
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