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3 years ago

What is the area of a rectangle with width 25 inches and length 35 inches? 1/5 in² 6/25 in² 6/10 in² 2 in²

2 answers:

8 0

By looking at ur answer choices, I am assuming the width is 2/5 inches and the length is 3/5 inches.

A = L * W
A = 3/5 * 2/5
A = 6/25 in^2 <==

Eva8 [605]3 years ago

4 0

Answer:

6/25 in^2

Step-by-step explanation:

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You invest $1,100 in an account that has an annual interest rate of 2.1%, compounded continuously. How much money will be in the

uranmaximum [27]

$1100 x 1.021^7 = $1272 (whole number.)

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3 years ago

Given f(x) = X-7 and g(x) = x^2<br> Find f(g(4))

Sergio [31]

Answer:

Step-by-step explanation:

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2 years ago

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Find the roots of the quadratic equation w+w²/3=0

Daniel [21]

I assume that the equation you mean is below:

$\large \boxed{w + \frac{ {w}^{2} }{3} = 0}$

To find roots for this equation, we have to get rid of the denominator. We can do by multiplying both sides by 3.

$\large{w(3) + \frac{ {w}^{2} }{3} (3) = 0(3)} \\ \large{3w + {w}^{2} = 0}$

Factor w-term out (common factor)

$\large{w(3 + w) = 0} \\ \large{w = 0 \: \: \: or \: \: \: 3 + w = 0} \\ \large{w = 0, - 3}$

Answer

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8 0

2 years ago

PLEASE HELP (30 POINTS) Solve the rational equation x/3 = x^2/x + 5 , and check for extraneous solutions.

anygoal [31]

Option C: $x=0$ and $x=\frac{5}{2}$ are the solutions.

Explanation:

The equation is $\frac{x}{3} =\frac{x^{2} }{x+5}$

We shall determine the value of x, by simplifying the equation.

$\begin{aligned} x(x+5) &=3 x^{2} \\ x^{2}+5 x &=3 x^{2} \\ 2 x^{2}-5 x &=0 \\ x(2 x-5) &=0 \end{aligned}$

Thus, $x=0$ and $x=\frac{5}{2}$ are the solutions.

Now, let us check whether the solutions are extraneous solutions.

Let us substitute $x=0$ in the original equation to check whether both sides of the equation are equal.

$\begin{aligned}&\frac{0}{3}=\frac{0^{2}}{0+5}\\&0=\frac{0}{5}\\&0=0\end{aligned}$

Thus, both sides of the equation are equal.

Hence $x=0$ is a true solution.

Now, Let us substitute $x=\frac{5}{2}$ in the original equation to check whether both sides of the equation are equal.

$\begin{aligned}\frac{\left(\frac{5}{2}\right)}{3} &=\frac{\left(\frac{5}{2}\right)^{2}}{\left(\frac{5}{2}\right)+5} \\\frac{5}{6} &=\frac{\left(\frac{25}{4}\right)}{\left(\frac{15}{2}\right)} \\\frac{5}{6} &=\frac{5}{6}\end{aligned}$

Thus, both sides of the equation are equal.

Hence, $x=\frac{5}{2}$ is a true solution.

Thus, solutions are not extraneous.

Hence, Option C is the correct answer.

8 0

3 years ago

300 has how many<br> 2/3 in it?

coldgirl [10]

450

hope this helps !!!

8 0

2 years ago

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