The answer would be 6. This be because 6 + -8 = -2.
2/9 3/5 5/7 is the correct answer
For the first boat, 6 knots at a bearing of N39, and for the second boat 4 knots at a bearing of S87°W. the distance of boats at the end of 2 hr and the bearing of 1st to 2nd both is mathematically given as
<h3>What is the distance b/w the boats at the end of 2 hr and the bearing of 1st to 2nd boat?</h3>
Generally, the Relative speed is mathematically given as
V=\sqrt{4^2+6^2+2(4)(6)cos(48)}
V=\sqrt{52+48(0.669)}
X=9.17Knots
Hence, distance b/w the boats
V'=9.17Knots*2
V'=18.34
V'=22.93Km
In conclusion, the bearing of 1st to 2nd boa ist
B=39+90+(90-87)
B=132°
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brainly.com/question/4931057
Answer:
-(x-y)
Step-by-step explanation:
-(x-2y) - y
-x+2y -y
-x+y
-(x-y)
