Upon a slight rearrangement this problem gets a lot simpler to see.
x^3-x+2x^2-2=0 now factor 1st and 2nd pair of terms...
x(x^2-1)+2(x^2-1)=0
(x+2)(x^2-1)=0 now the second factor is a "difference of square" of the form:
(a^2-b^2) which always factors to (a+b)(a-b), in this case:
(x+2)(x+1)(x-1)=0
So g(x) has three real zero when x={-2, -1, 1}
Answer:
show us the graphs to be able to tell you which one
Step-by-step explanation:
Answer:
square root of 2 or if needed simplified, 1.414213 to the nearest millionth.
Step-by-step explanation:
Start with the equation d= square root of (11-10)^2+(4-5)^2 where that is simplified to square root of (1)^2+(-1)^2 to square root of 1+1 to your final answer, square root of 2. Also simplified to 1.414213.
