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Y_Kistochka [10]
3 years ago
14

Klingon Widgets, Inc., purchased new cloaking machinery four years ago for $8 million. The machinery can be sold to the Romulans

today for $7.4 million. Klingon’s current balance sheet shows net fixed assets of $6 million, current liabilities of $790,000, and net working capital of $246,000. If all the current accounts were liquidated today, the company would receive $1.13 million cash.
What is the book value of Klingon’s total assets today? (Enter your answer in dollars, not millions of dollars, e.g., 1,234,567.)
Book value of total assets $
What is the sum of the market value of NWC and the market value of fixed assets? (Do not round intermediate calculations. Enter your answer in dollars, not millions of dollars, e.g., 1,234,567.)
Sum of the market value of NWC and market value of fixed assets $
Business
1 answer:
alisha [4.7K]3 years ago
7 0

Answer and Explanation:

The computation is shown below:

But before that we need to find out the current asset which is

The Net working capital = Current assets - current liabilities

$246,000 = Current assets -$790,000

So, the current assets is $1,036,000

Now the book value of Klingon’s total assets is

Total assets = Current assets + net fixed assets

= $1,036,000 + $6,000,000

= $7,036,000

The sum of market value of NWC and fixed assets is

= Market value of net working capital + market value of fixed assets

= $1,130,000 + $7,400,000

= $8,530,000

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You plan to invest in bonds that pay 6.0%, compounded annually. If you invest $10,000 today, how many years will it take for you
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The answer is 16 years.

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The formula for calculating the value of an investment that is compounded annually is given by:

V(n)=(1+R)^nP

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R is the annual interest rate,

P is the principal investment.

We know the following:

25000=(1+0.06)^n \times 10000

And we want to clear the value <em>n</em> from the equation.

The problem can be resolved as follows.

<u>First step:</u> divide each member of the equation by 10,000:

\frac{ 25000}{10000}=(1+0.06)^n \times \frac{ 10000}{10000}

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<u>Second step:</u> apply logarithms to both members of the equation:

log(2.5)=log (1.06)^n

<u>Third step:</u> apply the logarithmic property logA^n=n.logA in the second member of the equation:

log(2.5)=n.log (1.06)

Fourth step: divide both members of the equation by log1.06

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We can round up the number and conclude that it will take 16 years for $10,000 invested today in bonds that pay 6% interest compounded annually, to grow to $25,000.

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