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Flauer [41]
3 years ago
5

A parallelogram with a height of 2x+3 has an area of 2x^2+13x+15. What is the length of the base of the parallelogram? Please sh

ow work.
Mathematics
2 answers:
OlgaM077 [116]3 years ago
8 0

(2x^2+13x+15)/2x+3=x+5

Use long or synthetic division to solve this problem.

rosijanka [135]3 years ago
8 0

Answer : The length of the base of the parallelogram is, x+5

Step-by-step explanation :

As we know that:

Area of parallelogram = Height × Base

Given:

Height of parallelogram = 2x+3

Area of parallelogram = 2x^2+13x+15

Now put all the given values in the above formula, we get:

Area of parallelogram = Height × Base

2x^2+13x+15 = 2x+3 × Base

Base = \frac{2x^2+13x+15}{2x+3}

Now factorize this expression 2x^2+13x+15, we get:

Base = \frac{2x^2+(10x+3x)+15}{2x+3}

Base = \frac{2x(x+5)+3(x+5)}{2x+3}

Base = \frac{(2x+3)(x+5)}{2x+3}

Base = x+5

Therefore, the length of the base of the parallelogram is, x+5

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