A polygon has an area of 225 square meters. If the area is tripled, how does each side length change?

1 answer:

3 0

Let me tell you the process so that you get to the answer
Remember first that the area of a regular polygon with x sides has each of them a length which can be represented by y

A = 1/4 * xy^2 * Cot(180/x) 
The purpose is to solve for y, so we get 
y^2 = 4A/(xCot(180/x)) 
y = √(4A/(xCot(180/x)))

The thing we need to change is A in the previous formula and with that we can use the equaation to be a constant. This could be represented by Z
Z = √(4/(xCot(180/x)))
so
Y = Z√A
If we increase area by a factor s, y increases by a factor of √x.
So if you want to know the triple then you need to increase it by √3

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Step-by-step explanation:

We are given the following in the question:

Offense: 325, 292, 316, 308, 325, 263, 302, 311, 265, 329, 267, 324

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$Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}$