Answer:
x^0 y^-3 / x^2 y^-1
= 1 / x^2 y^-1 (y^3) ...because x^0 = 1 and [(y^-1) (y^3)] = y^2
= 1/(x^2 y^2)
Past due balance = $87.50
Late fee = 15% of $87.50 = 0.15*87.50 = $13.125
New charges = $75.00
New total = 87.50 + 13.125 + 75 = $175.625
Answer: The new total is $175.63
Answer: The greatest number of rows Li Na can plant is 9.
Step-by-step explanation:
Given: Li Na is going to plant 63 tomato plants and 81 rhubarb plants.
Li Na would like to plant the plants in rows where each row has the same number of tomato plants and each row has the same number of rhubarb plants.
To find the greatest number of rows Li Na can plant, we need to find the GCF of 63 and 81.
Since , 
Clearly, GCF(63,81)=9
Therefore, the greatest number of rows Li Na can plant is 9.
Answer:
your answer for 300+480=780 . that was on Saturday , now you have $780 the carvinal..raised 1480 .
Step-by-step explanation:
tell me if I'm wrong thank u (: