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7nadin3 [17]
3 years ago
14

On Monday, Anya read 11 pages of a book in 1/2 hour. On Tuesday, she read 18 pages in 3/4 hour. Did Anya's reading speed increas

e by more than 10% from Monday to Tuesday? Justify your answer.
Mathematics
1 answer:
Lerok [7]3 years ago
4 0
The way you should go about solving this really depends on how your teacher taught you...However, here's what I would recommend...
You know that 1/2 an hour is equal to 30 minutes, and 3/4 of an hour is equal to 45 minutes.
Using this you can  then solve for how many pages she read per minute by dividing the number of pages read by the number of minutes read:11 pages/ 30 minutes to give you Monday's reading speed,and18 pages/ 45 minutes to give you Tuesday's reading speed.

Next, to calculate a percentage increase you need to do the following:
1. Determine the difference between the speeds (this means you will subtract Monday's reading speed from Tuesday's reading speed.)
2. Next you take that number and divide it by Monday's reading speed.
3. Multiply that answer by 100 to get the percentage.

I'm not going to tell you the speeds, as you should try to attempt to solve it by yourself, and I'm sure you need to show your work. I will however tell you that you should find there was a 3.3% increase from Monday to Tuesday.

If you need more help, let me know!  
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Natalija [7]

Answer:

-3.2 is the smallest integer  

Step-by-step explanation:

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%28x%5E%7B2%7D%20%2Bx-3%29%3A%20%28x%5E%7B2%7D%20-4%29%5Cgeq%201" id="TexFormula1" title="(x^{
Jlenok [28]

Answer:

x>2

Step-by-step explanation:

When given the following inequality;

(x^2+x-3):(x^2-4)\geq1

Rewrite in a fractional form so that it is easier to work with. Remember, a ratio is another way of expressing a fraction where the first term is the numerator (value over the fraction) and the second is the denominator(value under the fraction);

\frac{x^2+x-3}{x^2-4}\geq1

Now bring all of the terms to one side so that the other side is just a zero, use the idea of inverse operations to achieve this:

\frac{x^2+x-3}{x^2-4}-1\geq0

Convert the (1) to have the like denominator as the other term on the left side. Keep in mind, any term over itself is equal to (1);

\frac{x^2+x-3}{x^2-4}-\frac{x^2-4}{x^2-4}\geq0

Perform the operation on the other side distribute the negative sign and combine like terms;

\frac{(x^2+x-3)-(x^2-4)}{x^2-4}\geq0\\\\\frac{x^2+x-3-x^2+4}{x^2-4}\geq0\\\\\frac{x+1}{x^2-4}\geq0

Factor the equation so that one can find the intervales where the inequality is true;

\frac{x+1}{(x-2)(x+2)}\geq0

Solve to find the intervales when the equation is true. These intervales are the spaces between the zeros. The zeros of the inequality can be found using the zero product property (which states that any number times zero equals zero), these zeros are as follows;

-1, 2, -2

Therefore the intervales are the following, remember, the denominator cannot be zero, therefore some zeros are not included in the domain

x\leq-2\\-2

Substitute a value in these intervales to find out if the inequality is positive or negative, if it is positive then the interval is a solution, if it is negative then it is not a solution. This is because the inequality is greater than or equal to zero;

x\leq-2   -> negative

-2   -> neagtive

-1\leq x   -> neagtive

x>2   -> positive

Therefore, the solution to the inequality is the following;

x>2

6 0
3 years ago
Ping's Ice Cream Palace offers a special sundae that contains over 2 kilograms of ice cream plus any number of toppings. Write a
hjlf

Let "x" represent the weight of the toppings. We know that we can have any number of toppings. This means that one may ask for no toppings at all too.

Now, we have been told that "S" is the weight of the special sundae in kilograms. This definitely included the "mandatory" 2 kilograms of ice cream. Therefore, S will be at-least equal to 2.

Thus, the inequality that describes S, the weight of the special sundae in kilograms at Ping's Ice Cream Palace is given as:

S\geq 2+x kilograms.

It can be seen that as x increases, S increases too and if an order does not want any toppings in it then the weight of the special sundae will be a minimum of 2 kg which is the weight of the ice cream.

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3 years ago
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Dmitriy789 [7]

Answer:

first do 9x40 and get your answer then do 18x3 and get that answer and then add to do answers together

7 0
3 years ago
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Serhud [2]
Red to yellow.......7:3....added = 10
so 7/10 of the total students wore red and 3/10 of the total students wore yellow

and there are 300 total students...
7/10(300) = 2100/10 = 210 wore red
3/10(300) = 900/10 = 90 wore yellow

how many more wore red.....(210 - 90) = 120 more students wore red then yellow
5 0
3 years ago
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