Answer:
Excuse me but they is nothing shown below!
Step-by-step explanation: Again not trying to be rude but there is nothing shown below! thank you for your time! <3
Answer:
The relation is not a function
The domain is {1, 2, 3}
The range is {3, 4, 5}
Step-by-step explanation:
A relation of a set of ordered pairs x and y is a function if
- Every x has only one value of y
- x appears once in ordered pairs
<u><em>Examples:</em></u>
- The relation {(1, 2), (-2, 3), (4, 5)} is a function because every x has only one value of y (x = 1 has y = 2, x = -2 has y = 3, x = 4 has y = 5)
- The relation {(1, 2), (-2, 3), (1, 5)} is not a function because one x has two values of y (x = 1 has values of y = 2 and 5)
- The domain is the set of values of x
- The range is the set of values of y
Let us solve the question
∵ The relation = {(1, 3), (2, 3), (3, 4), (2, 5)}
∵ x = 1 has y = 3
∵ x = 2 has y = 3
∵ x = 3 has y = 4
∵ x = 2 has y = 5
→ One x appears twice in the ordered pairs
∵ x = 2 has y = 3 and 5
∴ The relation is not a function because one x has two values of y
∵ The domain is the set of values of x
∴ The domain = {1, 2, 3}
∵ The range is the set of values of y
∴ The range = {3, 4, 5}
Answer:
p(x) = (5x - 1) (x + 3)
Step-by-step explanation:
I apologize if I couldn't answer correctly, the question was a bit hard to understand because of the formatting.
Also I didn't see my answer in the list of answer choices but here it is:
if the polynomial has zeros at 0.2 and -3 the equation would have to be:
p(x)=(x-0.2)(x+3)
This is because plugging either of those numbers into the polynomial would cause it to equal 0.
(x-0.2) can be simplified by multiplying everything in the parenthesis by 5, getting rid of all of the decimals, making the final answer:
p(x) = (5x - 1) (x + 3)
SohCahToa
Sin=oposite side/hyptoonuse
Cos=adjacent side/hypotonuse
Tan=oposite side/hypotonuse
oposite side is the side oposite the angle
adjacent side is the side touching the angle that isn't the hypotonuse
hypotonuse is longest side
1.
first solve for hypotonuse using a²+b²=c²
hypotonuse=13
sinA=12/13
cosA=5/13
tanA=12/5
sinB=5/13
cosB=12/13
toa=5/12
2. the missing side is 8
sinD=15/17
cosD=5/17
tanD=15/5=3
sinE=5/17
cosE=15/17
tanE=5/15=1/3
3. missing side is 25
you should be able to do this
sinG=7/25
do the rest
4.
missing side is 6
sinJ=6/10=3/5
do the rest
