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Reil [10]
2 years ago
7

How do I Simplify this equation with exponents?

Mathematics
1 answer:
balandron [24]2 years ago
7 0
If an equation uses a number that has a square root, you can use that.

For example, 10 x 16 = 160.
You could simplify this into..
                      10 x 4² = 160.

Same thing with 100 + 144 = 244
The equation would become 10² x 12² = 244

I hope this was what you were asking, its the best I could do without you providing us an equation.
You might be interested in
Joshua started cycling at 5:15 pm By 8:09 pm, he has covered a distance of 7250 mWhat was Joshua's average speed during that tim
vivado [14]

The average speed of Joshua during that time is 2500 m/h.

Explanation:

It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.

The total time taken by Joshua from 5:15 pm to 8:09 pm is

2 { h } 54 \text { min }=2 \mathrm{h}+\frac{54}{60} {h}

Dividing we get,

2 { h } 54 \text { min }=2 \mathrm{h}+0.9 {h}

Adding, we have,

2 { h } 54 \text { min }=2.9 {h}

Thus, the total time taken by Joshua is 2.9 {h}

To determine the average speed we use the formula,

speed=\frac{distance}{time}

where distance=7250 and time=2.9

Hence, substituting the values we have,

speed=\frac{7250}{2.9}

Dividing, we get,

speed=2500

Thus, the average speed of Joshua during that time is 2500 m/h.

5 0
3 years ago
Please help me <br> 3(x + 2) * 10 * 7 divided by 70 - 2 (x+2)<br><br> Simplify
I am Lyosha [343]

Answer:

= 105(x+2)/33-x

Step-by-step explanation:

Given the expression

[3(x+2)*10*7]÷70 - 2(x+2)

= 3(x+2)*70÷70 - 2(x+2)

= 210(x+2)/70-2x-4

= 210(x+2)/66-2x

= 210(x+2)/2(33-x)

= 105(x+2)/33-x

8 0
2 years ago
YO IS THIS RIGHT!??????? 12 POINNNTTTSS BOI
Amiraneli [1.4K]

Click off the first one because 180 (Thea) < 225 (Eleanor). Then keep the second one and click the third and fourth one.

3 0
3 years ago
Question 1 of 12, Step 1 of 1
stellarik [79]

Answer:

325 and 375 mph

Step-by-step explanation:

Given :

Distance between plane A and B = 2800

Recall :

Distance = speed * time

Let speed of A = v1

Speed of B = v2

v1 = v2 + 50

Time taken = 4 hours

Distance = speed * time

Total distance = 2800

2800 = v1 * 4 + v2 * 4

2800 = (4v1) + (4v2)

2800 = 4(v2+50) + 4v2

2800 = 4v2 + 200 + 4v2

2800 = 8v2 + 200

2800 - 200 = 8v2

2600 = 8v2

v2 = 2600/8

v2 = 325 mph

v1 = v2 + 50

v1 = 325 + 50

v1 = 375 mph

8 0
2 years ago
What is the equation for a circle with a center at (-2,-4) that passes through the point (3,8)?
Margarita [4]
Check the picture below.

so, the center of the circle is the midpoint of that diametrical segment, and half that length is the radius.

\bf ~~~~~~~~~~~~\textit{middle point of 2 points }&#10;\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&&(~ -2 &,& -4~) &#10;%  (c,d)&#10;&&(~ 3 &,& 8~)&#10;\end{array}\qquad&#10;%   coordinates of midpoint &#10;\left(\cfrac{ x_2 +  x_1}{2}\quad ,\quad \cfrac{ y_2 +  y_1}{2} \right)&#10;\\\\\\&#10;\left( \cfrac{3-2}{2}~~,~~\cfrac{8-4}{2} \right)\implies \left( \frac{1}{2}~,~2 \right)\impliedby center

\bf ~~~~~~~~~~~~\textit{distance between 2 points}&#10;\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&&(~ -2 &,& -4~) &#10;%  (c,d)&#10;&&(~ 3 &,& 8~)&#10;\end{array}~~~ &#10;%  distance value&#10;d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}&#10;\\\\\\&#10;d=\sqrt{[3-(-2)]^2+[8-(-4)]^2}\implies d=\sqrt{(3+2)^2+(8+4)^2}&#10;\\\\\\&#10;d=\sqrt{25+144}\implies d=\sqrt{169}\implies d=13\qquad\qquad \qquad  \stackrel{radius}{\frac{13}{2}}

\bf \textit{equation of a circle}\\\\ &#10;(x- h)^2+(y- k)^2= r^2&#10;\qquad &#10;center~~(\stackrel{\frac{1}{2}}{ h},\stackrel{2}{ k})\qquad \qquad &#10;radius=\stackrel{\frac{13}{2}}{ r}&#10;\\\\\\&#10;\left( x-\frac{1}{2} \right)^2+(y-2)^2=\left( \frac{13}{2} \right)^2\implies \left( x-\frac{1}{2} \right)^2+(y-2)^2=\frac{169}{4}

3 0
3 years ago
Read 2 more answers
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