Given :
The percent of concentration of a certain drug in the bloodstream x hours after the drug is administered is given by
.
To Find :
Find the time at which the concentration is a maximum. b. Find the maximum concentration.
Solution :
For maximum value of x, K'(x) = 0.

Since, time cannot be negative, so ignoring x = -3 .
Putting value of x = 3, we get, K(3) = 15/( 9 + 9) = 5/6
Therefore, maximum value drug in bloodstream is 5/6 at time x = 3 units.
Hence, this is the required solution.
Justify means plug answer in and verify
so distribute 8(3-7x)=24-56x
143=7+24-56x
143=31-56x
minus 31 both sides
112=-56x
divide both sides by -56
-2=x
justify
plug it back
143=7+8(3-7x)
143=7+8(3-7(-2))
143=7+8(3-(-14))
143=7+8(3+14)
143=7+8(17)
143=7+136
143=143
true
x=-2
Answer:No it cannot,
Step-by-step explanation:
A prime number is any number that is pime doesnt matter what number as long as it is a prime number it can be a multiple techically,but not offen depends but in this case most likely not
Answer:
y = -5x + 20
Step-by-step explanation:
Lets start with the first given values for x and y
(2,10)
Lets try out the first equation
y = 5x + 4
y = 5(2) + 4
y = 14
This equation wouldn't work because the y value is not 10 when the x value is 2
y = 5x + 20
y = 5(2) + 20
y = 30
This equation doesn't work either
y = -5x + 20
y = -5(2) + 20
y = -10 + 20
y = 10
This would be the correct equation since your y value is 10 when the x value is 2
Answer:
D
Step-by-step explanation:
the company is it a big company with you in my neighborhood that is a lot more expensive and more expensive to