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3 years ago

WILL MARK BRAINLIEST!!! PLZ HELP!!!

Mathematics

2 answers:

nika2105 [10]3 years ago

7 0

Answer:

x = -5.

Step-by-step explanation:

The solutions of the equation is when the two functions intersect. That is at (-5, 5.5), so where x = -5.

Hope this helps!

TEA [102]3 years ago

7 0

Answer:

x = -5

Step-by-step explanation:

f(x) = g(x) has more than one solution, because they intersect at two points.

The question asks for one solution of f(x) = g(x).

One point where they intersect is at (-5, 5.5), as shown in the graph.

(x , y)

x = -5, y = 5.5

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at maximum speed , an airplane travels 1680 miles against the wind in 5 hours flying with the wind , the plane can travel the sa

Westkost [7]

X = velocity of plane
y = velocity of wind

x - y = 1680/5 = 336 mph .....(1) [ plane flying against the wind]
&
x + y = 1680/4 = 420 mph....(2) [ plane flying with the wind]

Adding (1) and (2) to eliminate y gives

2x = 756
x = 378 mph is the speed of the plane with no wind.

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3 years ago

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Lamaj is rides his bike over a piece of gum and continues riding his bike at a constant rate time = 1.25 seconds the game is at

Hitman42 [59]

Lamaj rides his bike over a piece of gum and continues riding his bike at a constant rate. At time = 1.25 seconds, the gum is at a maximum height above the ground and 1 second later the gum is on the ground again.

a. If the diameter of the wheel is 68 cm, write an equation that models the height of the gum in centimeters above the ground at any time, t, in seconds.

b. What is the height of the gum when Lamaj gets to the end of the block at t = 15.6 seconds?

c. When are the first and second times the gum reaches a height of 12 cm?

Answer:

Step-by-step explanation:

We are being told that:

Lamaj rides his bike over a piece of gum and continues riding his bike at a constant rate. This keeps the wheel of his bike in Simple Harmonic Motion and the Trigonometric equation that models the height of the gum in centimeters above the ground at any time, t, in seconds. can be written as:

$\mathbf {y = 34cos (\pi (t-1.25))+34}$

where;

y = is the height of the gum at a given time (t) seconds

34 = amplitude of the motion

the amplitude of the motion was obtained by finding the middle between the highest and lowest point on the cosine graph.

$\mathbf{ \pi}$ = the period of the graph

1.25 = maximum vertical height stretched by 1.25 m to the horizontal

b) From the equation derived above;

if we replace t with 1.56 seconds ; we can determine the height of the gum when Lamaj gets to the end of the block .

So;

$\mathbf {y = 34cos (\pi (15.6-1.25))+34}$

$\mathbf {y = 34cos (\pi (14.35))+34}$

$\mathbf {y = 34cos (45.08)+34}$

$\mathbf{y = 58.01}$

Thus, the gum is at 58.01 cm from the ground at t = 15.6 seconds.

When are the first and second times the gum reaches a height of 12 cm

This indicates the position of y; so y = 12 cm

From the same equation from (a); we have :

$\mathbf {y = 34 cos(\pi (t-1.25))+34}$

$\mathbf{12 = 34 cos ( \pi(t-1.25))+34}$

$\dfrac {12-34}{34} = cos (\pi(t-1.25))$

$\dfrac {-22}{34} = cos(\pi(t-1.25))$

$2.27 = (\pi (t-1.25)$

t = 2.72 seconds

Similarly, replacing cosine in the above equation with sine; we have:

$\mathbf {y = 34 sin (\pi (t-1.25))+34}$

$\mathbf{12 = 34 sin ( \pi(t-1.25))+34}$

$\dfrac {12-34}{34} = sin (\pi(t-1.25))$

$\dfrac {-22}{34} = sin (\pi(t-1.25))$

$-0.703 = (\pi(t-1.25))$

t = 2.527 seconds

Hence, the gum will reach 12 cm first at 2.527 sec and second time at 2.72 sec.

7 0

3 years ago

Can anyone help me with this please

olga_2 [115]

Hi there!

$\large\boxed{\frac{1}{4}, -\frac{3}{2}}$

13y² + 10y - 3 = 5y²

Begin by moving all terms to one side:

13y² + 10y - 3 - 5y² = 0

Combine like terms:

8y² + 10y - 3 = 0

Factor using the guess-and-check method.

(4y - 1)(2y + 3) = 0

Set each factor equal to 0 to find the solutions:

4y - 1 = 0

4y = 1

y = 1/4

2y + 3 = 0

2y = -3

y = -3/2

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3 years ago

Kate walks half a mile to the library how many yards does she walk

Crank

Theres 1760 yards in a mile so divide that by 2.
answer is 880

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4 years ago

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How to explain math problems to 3rd grader

hjlf

Answer:

Step-by-step explanation:

This is a super question and it is an excellent exercise for you. When I was teaching, once every term, I would ask my physics class to explain acceleration to a 7 year old. The stats favored the older women (mothers) who took the class. Almost none of the guys could do it. Here's why.

The sentences had to be very short. They were barely 6 or 7 words long. They were complete sentences.
The examples used had to be very simple. The secret to those mother's answers was they invariably picked something like a stop sign. They all knew that and they always got it right for those reasons.

You are trying to teach a seven or eight year old. Believe it or not, the first thing you have to do is check and see if they know their facts. Can they do 7+8 or 9+ 6 without hesitancy. If they can do those facts do they know the multiplication facts. 4 * 5 etc. They must know those things cold, or you are wasting your time. Don't ask me why. But you can't go on without those 2 fact types solid.

I take it you are trying to do word problems. The best thing you can do is teach them to read.

A man has a dime and a nickel and a penny. How much money does he have? Us a marker to underline the key statement.

a dime,

a nickel

a penny should be underlined. Don't ask for an answer - yet.

======

Keep doing this problem over and over. You are not trying to get an answer. You are trying to get them to understand how to read a question

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3 years ago

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