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otez555 [7]
3 years ago
8

Directions: Read the following questions. Write the letter of the

Mathematics
2 answers:
kkurt [141]3 years ago
7 0
1.A
2D
3B
4B
5there isn’t picture there
12345 [234]3 years ago
3 0

Answer:

1. A

2.D

3.B (parallel lines)

4.B

5. i don't have a picture of the figure so i'm not sure

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Express the limit as a definite integral on the given interval. lim n→[infinity] n xi ln(1 + xi2) Δx, [2, 7] i = 1
xenn [34]

Answer:

Step-by-step explanation:

Consider \  the \ following \ series

\lim_{n \to \infty}  \sum \limits ^n_{i=1} x_i \ In ( 1+ x_i^2) \Delta x , [2,7]

Let's \ recall \ the \ explanation \  of definite \ integral \ in  \ terms  \ of  \ Riemann \ sum

\int^b_a \ f(x) \ dx =  \lim_{n \to \infty}  \sum \limits ^n_{i=1} \ f(x_i) \Delta x , \ where \ \Delta x = \dfrac{b-a}{n}

By  \ efinition,  \ the \  limit \   is \  then \  expressed \   as  \  integral

\lim_{n \to \infty} \sum ^a_{i=1} \ x_i \ In (1+x_i^2) \Delta x = \int^7_2 xIn (1+x^2) \ dx

7 0
3 years ago
What is the surface area of the outside of a cube shaped closed-top water tank whose edge length is 7.2 ft? Drag and drop the co
Gnoma [55]
The surface area of a cube is:

A=6s^2  (It is just the area of 6 sides (squares) all having an area of s^2)

A=7.2^3=373.248 ft^3
3 0
3 years ago
Which of the following is the solution to the equation x + 6.8 = 53.5?
gregori [183]
X+6.8=53.5
x=53.5-6.8
=46.7
5 0
3 years ago
Read 2 more answers
Students in the school band are selling calendars they earn 0.40 on each calendar They sell. Their goal is to earn more than 327
Alexxandr [17]

Answer:

130.8

Step-by-step explanation:

i just think that you times 0.40 and 327 and then press = and it should give you 130.8

i hope it works

5 0
3 years ago
How do i simplify this expression -(f+3g-7)
pogonyaev

Answer:

-f-3g+7

Step-by-step explanation:

The negative sign on the outside of the bracket makes the numbers inside the brackets, the opposite sign. (minus becomes + and vis verser)

Have a nice day!!!!!!!!!!! :-)

<u>KA</u>

7 0
3 years ago
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