An _observation_ is taken using the senses
Habitat isolation is likely to be most relevant in the case of trumpeters in the Amazon basin.
If trumpeters can not cross rivers, then they would be able to mate with trumpeters on the same side of the river but not on the other side- a form of prezygotic isolation.
what are trumpeters?
The term "trumpeter" comes from the deep, booming territorial call of these chicken-sized, long-necked, hunch-backed, small-headed, short-tailed, dark-plumed, long-legged birds that wander the jungle floors of South America.The land of South America that now the Amazon River and its tributaries drain is recognized as the Amazon basin.
learn more about Amazon basin here:-
brainly.com/question/14229038
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The bottleneck effect occurs when the majority of a population is destroyed due to natural disasters or human activity's. This reduces the size of the gene pool resulting in smaller variations from bird to bird. Gene mutation is the permanent change in the DNA or gene. Stabilizing selection occurs when genetic diversity decreases and the majority of the population stabilizes on a specific trait. The Founder effect occurs due to a smaller population leaving a larger population. This leaves the smaller population with smaller genetic variations. The correct answer is the Founder effect.
First, write out all combinations for the parents:
<u>SsBB</u>:
SB
sB
SB
sB
<u>ssBb</u>:
sB
sb
sB
sb
So now that you know what to put on as the x and y for the Punnett Square, set it up:
<u> | SB | sB | SB | sB </u>
<u>sB | SsBB | ssBB | SsBB | ssBB </u>
<u>sb | SsBb | ssBb | SsBb | ssBb </u>
<u>sB | SsBB | ssBB | SsBB | ssBB </u>
<u>sb | SsBb | ssBb | SsBb | ssBb </u>
Now, listing each possible genotype and the number of times they show up in the square:
SSBB
0 times
SSBb/SSbB
0 times
SSbb
0 times
SsBB/sSBB
4 times
SsBb/SsbB/sSBb/sSbB/
4 times
Ssbb/sSbb
0 times
ssBB
4 times
ssBb/ssbB
4 times
ssbb
0 times
Since there are only 4 genotypes are possible, set up ratios of those four:
SsBB:
4 times/16 total = .25 = 25%
SsBb:
4 times/16 total = .25 = 25%
ssBB:
4 times/16 total = .25 = 25%
ssBb:
4 times/16 total = .25 = 25%
This means that the<em> genotypes</em> have a 25% : 25% : 25% : 25% likelihood.
Now, let's figure out the phenotypes of the 4 genotypes:
SsBB:
Ss = dominant
BB = dominant
SsBb:
Ss = dominant
BB = dominant
ssBB:
ss = recessive
BB = dominant
ssBb:
ss = recessive
Bb = dominant
So we have 2/4 that are S-dominant B-dominant and 2/4 that are S-recessive B-dominant.
This means that the phenotypes are:
2/4 = 50% Thin stripes with black eyes, and
2/4 = 50% Thin stripes with gray eyes.
I hope this helped you out :)