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3 years ago

What is HALF PROJECTILE MOTION and what are some examples of it?

1 answer:

5 0

I think basically anything you throw vertically, from that point to its maximum height where you get a half semi circle.. or if you throw a ball horizontally, from that point to the point it comes to rest.

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A ball is thrown horizontally from a platform so that the initial height of the ball is 6.0 m above the level ground below. The

solniwko [45]

We can first obtain time of flight from vertical fall
Initial velocity U=0, d = 6 m, a = 9.8 m/s²
d = ut + 1/2 at²
6.0 = 0 + (1/2 × 9.80 t²)
t = √(12/9.8)
= 1.106 sec
Horizontal velocity = Vh = Dh/t
= 24.0 /1.106 s
= 21.69 m/s
The ball was thrown at a speed of 21.69 m/s

5 0

4 years ago

One glass microscope slide is placed on top of another with their left edges in con- tact and a human hair under the right edge

-Dominant- [34]

Answer:

A dark fringe

8 0

4 years ago

4. As a 500 N woman sits on the floor, the floor exerts a force on her of

monitta

Answer: 1000

Explanation:

Its double her weight

7 0

3 years ago

A new planet is discovered that has twice the Earth's mass and twice the Earth's radius. On the surface of this new planet a per

kirza4 [7]

Answer:

option B

Explanation:

Radius of new planet,R' = 2R

Mass of the earth, M' = 2 M

R and M is the Radius and Mass of the earth.

Weight of the person on earth = 500 N

Weight of the person in the new planet = ?

We know acceleration due to gravity is calculated by using formula

$g = \dfrac{GM}{R^2}$

now, acceleration due to gravity on the new planet

$g' = \dfrac{GM'}{R'^2}$

$g' = \dfrac{G(2M)}{(2R)^2}$

$g' =\dfrac{1}{2} \dfrac{GM}{R^2}$

$g' =\dfrac{g}{2}$

here acceleration due to gravity is half in new planet, so weight will also be half on the new planet.

Weight on the new plane is equal to $\dfrac{500}{2}$ = 250 N

correct answer is option B

5 0

3 years ago

A cosmic-ray electron moves at perpendicular to earth’s magnetic field at an altitude where the field strength is. what is the r

Harlamova29_29 [7]

4.266 m is the radius of the circular path the electron follows.

Given

Speed of electron (v) = 7.5 × 10⁶ m/s

Earth's Magnetic Field (B) = 1 × 10⁻⁵ T

We already know that

Mass of electron (m) = 9.1 × 10⁻³¹ kg

Charge on electron (q) = 1.6 × 10⁻¹⁹ C

According to the formula

Radius of circular path(r) = mass on electron × speed/ Charge × Magnetic field

Radius of circular path(r) = m × v/q × B

Put the values into the formula

r = 9.1 × 10⁻³¹ × 7.5 × 10⁶/ 1.6 × 10⁻¹⁹ × 10⁻⁵

On solving, we get

r = 4.266 m

Hence, 4.266 m is the radius of the circular path the electron follows.

Learn more about magnetic field here brainly.com/question/26257705

#SPJ4

6 0

2 years ago