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kobusy [5.1K]
3 years ago
7

What is the perimeter of ΔBDE?

Mathematics
2 answers:
Oksi-84 [34.3K]3 years ago
5 0
A = √1² + 2²
a = √1 + 4
a = √5
a ≈ 2.23

b = 4

c = √3² + 2²
c = √9 + 4
c = √13
c ≈ 3.6

P = a + b + c
P = 2.23 + 4 + 3.6
P = 6.23 + 3.6
P = 9.83

Perimeter of ΔBDE = 9.83 units
Black_prince [1.1K]3 years ago
5 0

Answer:

9.84 units.

Step-by-step explanation:

We will use distance formula to find the perimeter of the given triangle.

\text{Distance}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

\text{Distance between B and D}=\sqrt{(2-1)^2+(4-2)^2}

\text{Distance between B and D}=\sqrt{(1)^2+(2)^2}

\text{Distance between B and D}=\sqrt{1+4}

\text{Distance between B and D}=\sqrt{5}

\text{Distance between D and E}=\sqrt{(5-2)^2+(2-4)^2}

\text{Distance between D and E}=\sqrt{(3)^2+(-2)^2}

\text{Distance between D and E}=\sqrt{9+4}

\text{Distance between D and E}=\sqrt{13}

We can see the distance between B and E is 4 units (5-1).

\text{Perimeter of triangle BDE}=\sqrt{5}+\sqrt{13}+4

\text{Perimeter of triangle BDE}=9.841619252\approx 9.84

Therefore, the perimeter of triangle BDE is 9.84 units.

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