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Allushta [10]
3 years ago
5

The first term of a G.p are as follows: m, m^2+4, 16m find the 5th term

Mathematics
1 answer:
Anna35 [415]3 years ago
4 0

Answer:

512

Step-by-step explanation:

In a geometric sequence, the ratio between the second term and the first term is equal to the ratio between the third term and the second term.

(m² + 4) / m = 16m / (m² + 4)

Solve:

(m² + 4)² = 16m²

m² + 4 = 4m

m² − 4m + 4 = 0

(m − 2)² = 0

m = 2

The first three terms of the geometric sequence are therefore 2, 8, 32.

The common ratio is 4, and the first term is 2.  So the 5th term is:

a = 2 (4)⁵⁻¹

a = 512

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Find the area of an equilateral triangle (regular 3 Gon) with the given measurement 9 in perimeter a=SQ.in
blsea [12.9K]

Answer:

3.897 in^{2}

Step-by-step explanation:

equilateral triangles are also equiangular, meaning the have equal angles.

Triangle sum theory says that angles of a triangle add up to 180.

That means each angle is 60.

A = bh/2

You need the (h). The base of is 3.  Perimeter = 9, so each side is 3

Draw a perpendicular line for the height. The line cuts the base in half (1.5)

Using trigonometry you can find the height.

tan 60° = h/1.5

h = height, 1.5 is half of 3, 60° is the base angle.

multiply each side by 1.5

1.5(tan 60°) = h

h=2.598

then substitute h into formula

A= <u>(2.598)(3) </u>

           2

A = 3.897 rounded

4 0
3 years ago
A student must find the slope of a line that passes through the points (2.2) and (-1, 3). Which of the statements
Evgesh-ka [11]

Answer:

A

Step-by-step explanation:

the formula of the slope is (y2 - y1)/(x2 - x1)

slope = (3-2)/(-1-2) = 1/(-3) = -1/3

6 0
3 years ago
Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the
Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees wasx+\frac{1}{4} x=\frac{5}{4} x, and for the next three years we have that

                             Start                                          End

Second year     \frac{5}{4}x --------------   \frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x

Third year    (\frac{5}{4} )^{2}x-------------(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x

Fourth year (\frac{5}{4})^{3}x--------------(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.

So  the formula to calculate the number of trees in the fourth year  is  

(\frac{5}{4} )^{4} x, we know that all of the trees thrived and there were 6250 at the end of 4 year period, then  

6250=(\frac{5}{4} )^{4}x⇒x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.

Therefore the number of trees at the begging of the 4-year period was 2560.  

7 0
3 years ago
Find the volume.<br> Area = 16.4 cm²<br> 8.1 cm<br> cm³
Tasya [4]

Answer:

132.84 is the answer as volume is area times length

6 0
2 years ago
HELP PLEASE ASAP<br> what is the mean of 210,160,200 ?
MrRissso [65]
To find the mean, add all the numbers then divide by the amount of numbers there are to find the average.

210+160+200=570

570÷3=190

Answer: 190 



5 0
3 years ago
Read 2 more answers
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