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3 years ago

Which device assists with medical imaging? HELPPPP!!!!!!

Computers and Technology

1 answer:

FinnZ [79.3K]3 years ago

7 0

Answer:

<h2><u>Medical imaging equipment are manufactured using technology from the semiconductor industry, including CMOS integrated circuit chips, power semiconductor devices, sensors such as image sensors (particularly CMOS sensors) and biosensors</u></h2>

Explanation:

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3 years ago

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2 years ago

Write a C program that reads two hexadecimal values from the keyboard and then stores the two values into two variables of type

sattari [20]

Solution :

#include $$$$

//Converts $\text{hex string}$ to binary string.

$\text{char}$ * hexadecimal $\text{To}$ Binary(char* hexdec)

{

long $\text{int i}$ = 0;

char *string = $(\text{char}^ *) \ \text{malloc}$ (sizeof(char) * 9);

while (hexdec[i]) {

//Simply assign binary string for each hex char.

switch (hexdec[i]) {

$\text{case '0'}:$

strcat(string, "0000");

break;

$\text{case '1'}:$

strcat(string, "0001");

break;

$\text{case '2'}:$

strcat(string, "0010");

break;

$\text{case '3'}:$

strcat(string, "0011");

break;

$\text{case '4'}:$

strcat(string, "0100");

break;

$\text{case '5'}:$

strcat(string, "0101");

break;

$\text{case '6'}:$

strcat(string, "0110");

break;

$\text{case '7'}:$

strcat(string, "0111");

break;

$\text{case '8'}:$

strcat(string, "1000");

break;

$\text{case '9'}:$

strcat(string, "1001");

break;

case 'A':

case 'a':

strcat(string, "1010");

break;

case 'B':

case 'b':

strcat(string, "1011");

break;

case 'C':

case 'c':

strcat(string, "1100");

break;

case 'D':

case 'd':

strcat(string, "1101");

break;

case 'E':

case 'e':

strcat(string, "1110");

break;

case 'F':

case 'f':

strcat(string, "1111");

break;

default:

printf("\nInvalid hexadecimal digit %c",

hexdec[i]);

string="-1" ;

}

i++;

}

return string;

}

int main()

{ //Take 2 strings

char *str1 =hexadecimalToBinary("FA") ;

char *str2 =hexadecimalToBinary("12") ;

//Input 2 numbers p and n.

int p,n;

scanf("%d",&p);

scanf("%d",&n);

//keep j as length of str2

int j=strlen(str2),i;

//Now replace n digits after p of str1

for(i=0;i<n;i++){

str1[p+i]=str2[j-1-i];

}

//Now, i have used c library strtol

long ans = strtol(str1, NULL, 2);

//print result.

printf("%lx",ans);

return 0;

}

4 0

3 years ago

Write a program that prompts the user to enter a date, using integer values for the month, day, and year, and then prints out th

attashe74 [19]

Answer:

import datetime

user = input("Enter date in yyyy,m,d: ").split(",")

int_date = tuple([int(x) for x in user])

year, month, day =int_date

mydate = datetime.datetime(year, month, day)

print(mydate)

x = mydate.strftime("%B %d, %Y was a %A")

print(x)

Explanation:

The datetime python module is used to create date and time objects which makes it easy working with date-time values. The user input is converted to a tuple of integer items, then they are converted to date time objects and parsed to string with the strftime method.

5 0

2 years ago

Int[] myArray1= new int[24]; int[] myArray2= new int[10]; float[] myArray3= new float[8]; int index1, index =0 for(int index1 =0

anastassius [24]

Answer:

The value of myArray2[index2] when index1 = 12 is 30

Explanation:

In the source code, the formula for myArray2[index2] is;

myArray2[index2] = index2 + index3 + myArray1[index1],

myArray1[index1] = index1 * 2,

index2 = index % 10 (equal to the remainder) and

index3 = index % 8

When index1 increases to 12 in the for-loop statement, the "myArray1[index1]" is equal to 24, index2 is equal to 2 and index3 is 4. The total sum is equal to 30 and assigned to "myArray2[index2]".

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3 years ago