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kondaur [170]
3 years ago
12

What output is displayed when the code that follows is executed? HashMap sales = new HashMap<>(); sales.put("January", 389

.45); sales.put("February", 432.89); sales.put("March", 275.30); for (Map.Entry sale : sales.entrySet()) { System.out.println(sale.getKey() + ": " + sale.getValue()); }
Computers and Technology
1 answer:
White raven [17]3 years ago
8 0

Answer:

March: 275.30

January: 389.45

February: 432.89

Explanation:

The code to be executed is a Java code. Since the For loop used is based on Sale, when the code is complied it will print the output in the order of sale as below:

March: 275.30

January: 389.45

February: 432.89

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Answer:

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Novay_Z [31]

Answer:

#include <bits/stdc++.h>

using namespace std;

// Function to print even numbers

void printEvenNumbers(int N)

{

cout << "Even: ";

for (int i = 1; i <= 2 * N; i++) {

// Numbers that are divisible by 2

if (i % 2 == 0)

cout << i << " ";

}

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// Function to print odd numbers

void printOddNumbers(int N)

{

cout << "\nOdd: ";

for (int i = 1; i <= 2 * N; i++) {

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}

// Driver code

int main()

{

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return 0;

}

Explanation:

Note: This will find both odd and even numbers, you have to change the number above to the number of your choice

For even numbers

Even number are numbers that are divisible by 2.

To print even numbers from 1 to N, traverse each number from 1.

Check if these numbers are divisible by 2.

If true, print that number.

For odd numbers

Odd number are numbers that are not divisible by 2.

To print Odd numbers from 1 to N, traverse each number from 1.

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Explanation:

if I wrong please correction me!

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Hope this helps you

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3 years ago
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