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Step2247 [10]
3 years ago
11

What is the product in simplest form? State any restrictions on the variable. Please show your work.

Mathematics
2 answers:
Nutka1998 [239]3 years ago
7 0
The first term = \frac{y^2}{y-3}
The second term = \frac{y^2-y-6}{y^2+y} =  \frac{(y-3)(y+2)}{y(y+1)} ⇒ factoring the numerator and denominator

multiplying the both terms:
\frac{y^2}{y-3} * \frac{y^2-y-6}{y^2+y} = \frac{y^2}{y-3} * \frac{(y-3)(y+2)}{y(y+1)} 

= \frac{y^2}{y} * \frac{(y-3)(y+2)}{(y-3)(y+1)} =  \frac{y(y+2)}{y+1}






mote1985 [20]3 years ago
5 0
You have the following expressions given in the problem above:

 (y^2/y-3)(y^2-y-6/y^2+y)
 
 By applying the exponents properties, you can simplify it, as it shown below:

 (y^2/y-3)(y^2-y-6/y^2+y)
 (y^4-y^3-6y^2)/(y^3+y^2-3y2-3y)
 (y^4-y^3-6y^2)/(y^3-2y2-3y)

 Then, you have:
 y^2(y^2-y-6)/y(y^2-2y-3)
 (y^2-y-6)/(y^2-2y-3)

 The answer is: (y^2-y-6)/(y^2-2y-3)

 


 
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2 years ago
Jay estimates that a basketball weights about .5 pounds. Shawna estimates that a basketball weights about.05. Whose estimate is
Natasha_Volkova [10]

Answer:

Jay's estimate is closer to the actual weight of the basketball

Step-by-step explanation:

The standard weight of an NBA basketball is 1.4 pounds.

Judging the accuracy of Jay's and Shawna's answer based on their percentage error when compared with the standard, we have that Jay's answer has a lower error as shown below

Error  = (Standard value - Estimated value)/ Standard Value ×100

Error in Jays answer = \frac{1.4 - 0.5}{1.4} × 100 = 64.28 %

Error in Shawna's answer = \frac{1.4 - 0.05}{1.4} × 100 = 96.42%

From this, It is obvious that Jay's answer has a lower percentage error when compared to the actual value.

8 0
3 years ago
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Nesterboy [21]

Answer:

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5 0
2 years ago
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vladimir2022 [97]

Answer:

length:  200

width:  65

Step-by-step explanation:

length:  3w + 5

width:  w

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width:  w = 65

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