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Step2247 [10]
3 years ago
11

What is the product in simplest form? State any restrictions on the variable. Please show your work.

Mathematics
2 answers:
Nutka1998 [239]3 years ago
7 0
The first term = \frac{y^2}{y-3}
The second term = \frac{y^2-y-6}{y^2+y} =  \frac{(y-3)(y+2)}{y(y+1)} ⇒ factoring the numerator and denominator

multiplying the both terms:
\frac{y^2}{y-3} * \frac{y^2-y-6}{y^2+y} = \frac{y^2}{y-3} * \frac{(y-3)(y+2)}{y(y+1)} 

= \frac{y^2}{y} * \frac{(y-3)(y+2)}{(y-3)(y+1)} =  \frac{y(y+2)}{y+1}






mote1985 [20]3 years ago
5 0
You have the following expressions given in the problem above:

 (y^2/y-3)(y^2-y-6/y^2+y)
 
 By applying the exponents properties, you can simplify it, as it shown below:

 (y^2/y-3)(y^2-y-6/y^2+y)
 (y^4-y^3-6y^2)/(y^3+y^2-3y2-3y)
 (y^4-y^3-6y^2)/(y^3-2y2-3y)

 Then, you have:
 y^2(y^2-y-6)/y(y^2-2y-3)
 (y^2-y-6)/(y^2-2y-3)

 The answer is: (y^2-y-6)/(y^2-2y-3)

 


 
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