Question

Find the surface area of the triangular prism. 15.6 cm 10 cm 11 cm 12 cm

Answer 1

Answer:

533.6cm²

Step-by-step explanation:

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Area of each triangular base:

$\frac{1}{2}(12)(10)=60$

Area of the rectangular faces:

$12\times 11 =132$

$15.6\times 11=171.6$

$10\times 11=110$

Add to find the surface area:

$60+60+132+171.6+110=533.6$

Thus, the surface area of the triangular prism is = 533.6 yd²

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Answer 2

Answer:

Total Surface area of the figure = $533.6\,cm^2$

Step-by-step explanation:

 The figure consists of three rectangular faces and two triangular faces :

Area of the figure = Area of the two triangular faces + Area of the three rectangular faces

Area of the two triangular faces:

                               $2(\dfrac{1}{2} \times Base \times Height)$

$Base= 12\, cm\\Height=10\,cm$

Area of the two triangular faces is:

              $=2(\dfrac{1}{2} \times 12 \times 10)\\\\=2(\dfrac{1}{2} \times 120 )\\\\=120\,cm^2$

Area of the rectangle= $Length\times Width$

Area of the Rectangular face with :

$Length= 11\,cm\\Width=12\,cm$

                Area is:  

                             $=11\times 12\\\\=132\,cm^2$

Area of the rectangular face with:

$Length=15.6\,cm\\Width=11\,cm$

         Area is:

                            $=15.6\times 11\\=171.6\,cm^2$

For,

$Length=11\,cm\\Width=10\,cm$

              Area is:

                             $=11\times 10\\=110\,cm^2$

Total Surface area of the figure is:

$=120+132+171.6+110\\=533.6\,cm^2$