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watch the video it would help you understand what to do.
Answer:
Step-by-step explanation:
Given
Let
Undergraduates
Graduates
So, we have:
-- Total students
--- students to select
Required
From the question, we understand that 2 undergraduates are to be selected; This means that 2 graduates are to be selected.
First, we calculate the total possible selection (using combination)
So, we have:
Using a calculator, we have:
The number of ways of selecting 2 from 3 undergraduates is:
The number of ways of selecting 2 from 5 graduates is:
So, the probability is:
Answer:
505.4 in²
Step-by-step explanation:
½d2= 19×tan 35° = 19×0.7 = 13.3 in
d2 = 2×13.3 = 26.6 in
d1 = 2×19=38 in
the area of Rhombus =
½×38×26.6 = 505.4 in²
Answer:
0.15401
Step-by-step explanation:
Given that test statistic = 3.7408
From the question, we could deduce that, this is scenario could be analysed A ONE - WAY analysis of Variance method as it has one independent variable, Age subdivided into 3 levels
The test statistic value obtained is the Chisquare (χ²) value, which equals 3.7408
To Obtain the requested Pvalue, we need the degree of freedom, which is :
(Number of columns - 1) * (number of rows - 1)
Number of candidates = 2
Number of levels = 3
Hence,
Degree of freedom = (3 - 1) * (2 - 1) = 2 * 1 = 2
Using the Chisquare Pvalue calculator or distribution table :
χ²;3.7408, 2 = 0.154062
Pvalue = 0.1541
-x + 5y = 8
multiply this equation by 3
-3x + 15y = 24
now add it to the other equation ( elimination)
-3x + 15y = 24
3x + 7y = -2
-----------------------
0x + 22 y = 22
divide each side by 22
y =1
substitute into -x + 5y =8 to find x
-x + 5(1) = 8
-x + 5 = 8
-x =3
divide by -1
x =-3
Answer (-3,1)
Choice A
