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DerKrebs [107]
2 years ago
6

For a work banquet, Jack can spend no more than $200 on dessert. Fruit pies cost $9 each and cakes cost $20 each. Write the line

ar inequality that models the situation
Graph the inequality.​
Mathematics
1 answer:
harina [27]2 years ago
3 0

Answer:

he could do 20 pies and 1 cake P+C=200$

Step-by-step explanation:

P=pie

P=20

C=cake

C=1

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What is the slope of the line that passes through the points (-10,8)and (-15,-7)
balandron [24]

Answer:

m = 3

Step-by-step explanation:

Use the slope formula to find the slope  m .

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Determine which expression has a greater value -12+6-4 or -34 -3+39
patriot [66]

By looking at it, I can tell the second expression is greater due to a a large postive number that's being added to it. Let's solve.

-12+6=-6-4=-10

-34-3=-37+39=2

So, -34-3+39 is greater.

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A photo is 15 cm high and 9 cm wide Michael wants to but porcelain shrink it so it's height is 6 cm High how wide will it then b
weqwewe [10]

Answer:

3.6cm

Step-by-step explanation:

Given data

We are given that the dimension of the photo is

Height= 15cm

Width= 9cm

That is

            15cm height  will make 9cm width

hence    6cm height will make x widht

cross multiply

9*6= 15*x

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Hence the width will be 3.6cm

3 0
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A sequence that changes by multiplying by the same number
zmey [24]

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7 0
3 years ago
Find the particular solution that satisfies the differential equation and the initial condition.
Vesnalui [34]

Answer:

1) y =4x^2 +7

2) y =7s^2 -3s^4 +181

Step-by-step explanation:

Assuming that our function is y = f(x) for the first case and y=f(s) for the second case.

Part 1

We can rewrite the expression like this:

\frac{dy}{dx} =8x

And we can reorder the terms like this:

dy = 8 x dx

Now if we apply integral in both sides we got:

\int dy = 8 \int x dx

And after do the integrals we got:

y = 4x^2 +c

Now we can use the initial condition y(0) =7

7 = 4(0)^2 +c, c=7

And the final solution would be:

y =4x^2 +7

Part 2

We can rewrite the expression like this:

\frac{dy}{ds} =14s -12s^3

And we can reorder the terms like this:

dy = 14s -12s^3 dx

Now if we apply integral in both sides we got:

\int dy = \int 14s -12s^3 ds

And after do the integrals we got:

y = 7s^2 -3s^4 +c

Now we can use the initial condition y(3) =1

1 = 7(3)^2 -3(3)^4 +c, c=1-63+243=181

And the final solution would be:

y =7s^2 -3s^4 +181

7 0
4 years ago
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