Answer:
-30 ?
Not really sure what you mean by that but, -19-11= -30 is all I know.
∞
∑3(1/4)ⁿ⁻¹ ==> replace n by consecutive values, starting with 1
ⁿ=¹
f(1) = 3(1/4)⁰ = 3 x 1 (any number raised to o is equal to 1
f(2) = 3(1/4)¹ = 3 x 1/4
f(3) = 3(1/4)² = 3 x (1/4)²
f(4) = 3(1/4)³ = 3 x (1/4)³
f(5) = 3(1/4)⁴ = 3 x (1/4)⁴
And so on and so forth. Then we have found a pattern that is:
f(n) = 3(1/4)ⁿ⁻¹
and with this you can find any number providing you know n
Answer:
1.25
Step-by-step explanation:
Answer:
C (-6,-8) → C' (6,8)
D (-2,-8) → D' (2,8)
E (-2,-4) → E' (2,4)
F (-6,-4) → F' (6,4)
Step-by-step explanation:
When you rotate a point 180° counterclockwise about the origin, the point A (x,y) becomes A' (-x,-y). So, if the points are positive, they will become negative.
Because all the points are negative, rotating them 180° counterclockwise will make them positive.
Hope that helps.
Y=12-0.2x=-0.2x+12
the slop is -0.2