To calculate the length of the diagonal, use the Pythagorean theorem:
c^2 = a^2 + b^2, where c is the diagonal.
c^2 = 65^2 + 34^2
c^2 = 4225 + 1156
c^2 = 5381
c ~ 73.36
To the nearest tenth of a meter, the diagonal has a length of 73.4 m
This is the answer 6x^2+15x+9
Answer:
When t=2.1753 & t=.5746 , h=27
Don't worry, I got you. Also, my calculator does too.
We set h equal to 27, because we want the height to be 27 when we solve for t.
That leaves us with:
27 = 7 + 44t - 16t^2
Simplify like terms,
20 = 44t - 16t^2
Move 20 onto the right side, so we can use quadratic equation
44t - 16t^2 - 20 = 0 --> -16t^2 + 44t - 20
Using quadratic, you get
t=2.1753 & t=.5746
<u>poster confirmed : "It’s t=2.18 and t=0.57"</u>
<span>This problem is an
example of ratio and proportion. A ratio is a comparison between two different
things. You are given the equivalent distance of a 1 2/5
kilometers to 1 mile. Also you are given 4 miles. You are required to find the distance
in kilometers of 4 miles. The solution of this problem is,</span>
1 2/5
kilometers /1 mile = distance/ 4 miles
distance = (4
miles) (1 2/5 kilometers /1 mile)
<u>distance =
28/5 or 5.6 kilometers</u>
<u>There are 5.6
kilometers in 4 miles.</u>
Answer:
hope this helps you with your question
