From online resources gotten about this question, for quadrilateral EFGH and quadrilateral E'F'G'H to be congruent, what we must do first is to rotate 180° counterclockwise around the origin and then move EFGH onto E'F'G'H'.

The last step to get this proof of congruency is to reflect across the y-axis.

Read more about transformations at; brainly.com/question/4289712

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5 0

2 years ago

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

wel

Answer:

$z=\frac{15\sqrt{3}}{2}$

Step-by-step explanation:

In leftmost triangle:

opposite side =y

adjacent=a

now, we can use trig formula

$tan(60)=\frac{y}{a}$

now, we can solve for y

$y=atan(60)$

In rightmost triangle:

adjacent=b

opposite=y

a+b=15

b=15-a

now, we can use trig formula

$tan(30)=\frac{y}{15-a}$

now, we can solve for y

$y=(15-a)tan(30)$

now, we can set them equal

and then we can solve for a

$atan(60)=(15-a)tan(30)$

$\sqrt{3}a\cdot \:3=\frac{\sqrt{3}\left(15-a\right)}{3}\cdot \:3$

$4\sqrt{3}a=15\sqrt{3}$

$a=\frac{15}{4}$

now, we can find b

$b=15-\frac{15}{4}$

$b=\frac{45}{4}$

now, we can use trig formula

$cos(30)=\frac{b}{z}$

now, we can find z

$z=\frac{\frac{45}{4}}{cos(30)}$

we can simplify it

and we get

$z=\frac{15\sqrt{3}}{2}$

4 0

3 years ago

How do you write 2/9 as a %

Dmitriy789 [7]

The answer is 22.222222%.

5 0

3 years ago

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