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alexdok [17]
4 years ago
15

Find the value of x to the nearest tenth. Please help! ​

Mathematics
1 answer:
MakcuM [25]4 years ago
6 0

0.3 is the answer, hope this help you out! :D

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0.104 - 1.96\sqrt{\frac{0.104(1-0.104)}{500}}=0.0772

0.104 + 1.96\sqrt{\frac{0.104(1-0.104)}{500}}=0.1308

The 95% confidence interval would be given by (0.0772;0.1308)

Step-by-step explanation:

For this case we can calculate the estimated proportion like this:

\hat p =\frac{52}{500}= 0.104

We can assume that the normal model can be used since we satisfy two conditions:

np =500*0.104= 52>10

n(1-p) = 500*(1-0.104) = 448>10

The confidence level for this case is 95% of confidence, and the significance is given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

Replacing the values we got:

0.104 - 1.96\sqrt{\frac{0.104(1-0.104)}{500}}=0.0772

0.104 + 1.96\sqrt{\frac{0.104(1-0.104)}{500}}=0.1308

The 95% confidence interval would be given by (0.0772;0.1308)

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3 years ago
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